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horrorfan [7]
3 years ago
10

At what interest rate (to the nearest hundredth of a percent) compounded annually will money in savings double in five years?

Mathematics
1 answer:
Sphinxa [80]3 years ago
5 0
For a single payment with compound interest, the equation to use is F=P(1+i)^n where F is the value after n periods, P is the present value, and i is the interest rate.

If we want the final value F to double in 5 years, F is then equal to P then n=5. The equation is now:

2P=P(1+i)^5
2=(1+i)^5
i=14.87% per year
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1. Consider the data set 1,2,3,4,5,6,7,8,9.
ivanzaharov [21]

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b) Mean = 15, Median = 5

c) Due to presence of outlier i.e. 99.

Step-by-step explanation:

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1,2,3,4,5,6,7,8,9

Here, n = 9 which is odd

So, Mean would be

\dfrac{1+2+3+4+5+6+7+8+9}{9}=\dfrac{45}{9}=5

Median = (\dfrac{n+1}{2})^{th}=\dfrac{9+1}{2}=5^{th}=5

If 9 is replaced by 99,

1,2,3,4,5,6,7,8,99

So, mean would be

\dfrac{1+2+3+4+5+6+7+8+99}{9}=\dfrac{135}{9}=15

Median would be same as before i.e. 5

The mean is neither central nor typical for the data due to outlier i.e. 99

Hence, a) Mean = 5, Median = 5

b) Mean = 15, Median = 5

c) Due to presence of outlier i.e. 99.

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3 years ago
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Answer:

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