I think u forgot to put pic for we can see the triangle
Answer:
(1) 2π - x² = 0 (2) x = 2.5 cm (3) perimeter = 10 cm
Step-by-step explanation:
(1)The area of the circular coin without the inner square removed is πr² where r = 3 cm is the radius of the coin. So, the area of the coin without the inner square removed is πr² = π(3 cm)² = 9π cm²
The area of the square of x sides removed from its center is x².
The area A of the each face of the coin is thus A = 9π - x²
Since the area of each face of the coin A = 7π cm²,
then
7π = 9π - x²
9π - 7π - x² = 0
2π - x² = 0
(2) Solve the equation 2π - x² = 0
2π - x² = 0
x² = 2π
x = ±√(2π)
x = ± 2.51 cm
Since x cannot be negative, we take the positive answer.
So, x = 2.51 cm
≅ 2.5 cm
(3) Find the perimeter of the square
The perimeter of the square, p is given by p = 4x
p = 4 × 2.51 cm
= 10.04 cm
≅ 10 cm
Answer:
588 units^2
Step-by-step explanation:
To find the area of the enlarged rectangle, first find the length and width of the enlarged rectangle.
This is 3.5 multiplied by their original measures:
Length = 3.5 x 8 = 28
Width = 3.5 x 6 = 21
Now, area =. LxW = 588 units^2
Hope this helps
Answer:
(1) Area of second triangle= 50 cm^2.
(2) Area of ΔABC=98 cm^2.
and Area of ΔDFG=175 cm^2.
Step-by-step explanation:
<em>" For two similar triangles the ratio of sides is equal to the ratio of square of their areas".</em>
i.e. if a,b are the corresponding sides of two similar triangles and let A and B denote the area of two triangles then we have the relation as:
(1)
for the first question:
we have a=2, b=5.
A=8 cm^2.
Hence,
B=50 cm^2.
Hence, the area of second triangle is 50 cm^2.
(2)
In second option we have:
a=6 and b=5.
A-B=77 cm^2.
A=77+B
Hence area of second triangle i.e. ΔDFG is 175 cm^2.
and area of first triangle i.e. ΔABC=175-77=98 cm^2.
Answer:
Graph B
Step-by-step explanation:
