Suppose you add x liters of pure water to the 10 L of 25% acid solution. The new solution's volume is x + 10 L. Each L of pure water contributes no acid, while the starting solution contains 2.5 L of acid. So in the new solution, you end up with a concentration of (2.5 L)/(x + 10 L), and you want this concentration to be 10%. So we have

and so you would need to add 15 L of pure water to get the desired concentration of acid.
Answer:
x = -1
Step-by-step explanation:
1/2 = 2/4
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1/4x + 3/4 = 2/4
<u> -3/4 -3/4</u>
1/4x = -1/4
divide by -1/4
x = -1
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Answer:
x = -5
Step-by-step explanation:
You have to input the 5 into the x place. so it would be y=3(5) and you get the answer y=15