what are the values of a, b, and c in the quadratic equation 0 = x2 – 3x – 2? - a = , b = 3, c = 2 - a = , b = –3, c = –2 - a =

, b = 3, c = –2 - a = , b = –3, c = 2

Mathematics

1 answer:

Juliette [100K]3 years ago

3 0

$x^2-3x-2=0\\\\a=1;\ b=-3;\ c=-2\\\Delta=b^2-4ac\\\\\Delta=(-3)^2-4\cdot1\cdot(-2)=9+8=17 \ \textgreater \ 0\\\\then\\x_1=\dfrac{-b-\sqrt\Delta}{2a}\ and\ x_2=\dfrac{-b+\sqrt\Delta}{2a}\\\\x_1=\dfrac{3-\sqrt{17}}{2\cdot1}=\boxed{\dfrac{3-\sqrt{17}}{2}}\\\\x_2=\dfrac{3+\sqrt{17}}{2\cdot1}=\boxed{\dfrac{3+\sqrt{17}}{2}}$

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belka [17]

<h3>Answer:</h3>

$\boxed{\boxed{\pink{\bf \leadsto Hence \ option\ [d]\ \bigg(y = \dfrac{5}{2}x + 5\bigg) \ is \ correct }}}$

<h3>Step-by-step explanation:</h3>

Here from the given graph we can see that the graph the graph intersects x axis at (2,0) and y axis at (5,0). On seeing options it's clear that we have to use Slope intercept form . Which is :-

$\large\boxed{\orange{\bf y = mx + c} }$

We know that slope is $\tan\theta$ . So here slope will be ,

$\red{\implies slope = \tan\theta} \\\\\implies slope =\dfrac{PERPENDICULAR}{BASE} \\\\\bf \implies slope =\dfrac{5}{2}$

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$\purple{\implies y = mx + c }\\\\\implies y = \dfrac{5}{2}x + 5 \\\\\underline{\boxed{\red{\tt \implies y = \dfrac{5}{2}x + 5 }}}$

<h3>Hence option [ d ] is correct . </h3>

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3 years ago

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exis [7]

Answer:

Its false because

Step-by-step explanation:

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4 years ago

Read 2 more answers

A piece of wire measuring 20 feet is attached to a telephone pole as a guy wire. The distance along the ground from the bottom o

dem82 [27]

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Explanation:

Since we have given that

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