1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
sweet-ann [11.9K]
3 years ago
8

Brendan has 75 stamps in his collection. He puts 8 stamps on each page in his album. How many more stamps does he need to fill 1

0 pages with no left over?
Mathematics
1 answer:
nikklg [1K]3 years ago
3 0
75 stamps/8 stamps per page = 9 pages and 3 stamps remain.

He needs 5 STAMPS extra to fill 10 pages with no left over.
You might be interested in
A box is sitting on the floor. The box was then pulled with a force, Ft. The box did not move. The free-body diagram of the box
WINSTONCH [101]

Answer:

A

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Pls pls help ???!!!!
Blizzard [7]

Answer 3x3.4

Step-by-step explanation:

8 0
2 years ago
After 8 hours of snow, the
Dmitrij [34]
Answer: -21.125 or -21 1/8 degrees

Explanation: Divide the number of degrees (-169) by the amount of time it was snowing (8) to get the answer (-21.125).

-169÷8=-21.125
4 0
3 years ago
Graph the following linear function.<br> f(x) = 1/6x+3
Black_prince [1.1K]
Y-axis is 3
x-axis is -18

4 0
2 years ago
Solve the system of equations by finding the reduced row-echelon form of the augmented matrix for the system of equations.
Anuta_ua [19.1K]

Answer:

c

Step-by-step explanation:

First, we can transform this into a matrix. The x coefficients will be the first ones for each row, the y coefficients the second column, etc.

\left[\begin{array}{cccc}1&-2&3&-2\\6&2&2&-48\\1&4&3&-38\end{array}\right]

Next, we can define a reduced row echelon form matrix as follows:

With the leading entry being the first non zero number in the first row, the leading entry in each row must be 1. Next, there must only be 0s above and below the leading entry. After that, the leading entry of a row must be to the left of the leading entry of the next row. Finally, rows with all zeros should be at the bottom of the matrix.

Because there are 3 rows and we want to solve for 3 variables, making the desired matrix of form

\left[\begin{array}{ccc}1&0&0\\0&1&0\\0&0&1\end{array}\right] for the first three rows and columns. This would make the equation translate to

x= something

y= something

z = something, making it easy to solve for x, y, and z.

Going back to our matrix,

\left[\begin{array}{cccc}1&-2&3&-2\\6&2&2&-48\\1&4&3&-38\end{array}\right] ,

we can start by removing the nonzero values from the first column for rows 2 and 3 to reach the first column of the desired matrix. We can do this by multiplying the first row by -6 and adding it to the second row, as well as multiplying the first row by -1 and adding it to the third row. This results in

\left[\begin{array}{cccc}1&-2&3&-2\\0&14&-16&-36\\0&6&0&-36\end{array}\right]

as our matrix. * Next, we can reach the second column of our desired matrix by first multiplying the second row by (2/14) and adding it to the first row as well as multiplying the second row by (-6/14) and adding it to the third row. This eliminates the nonzero values from all rows in the second column except for the second row. This results in

\left[\begin{array}{cccc}1&0&10/14&-100/14\\0&14&-16&-36\\0&0&96/14&-288/14\end{array}\right]

After that, to reach the desired second column, we can divide the second row by 14, resulting in

\left[\begin{array}{cccc}1&0&10/14&-100/14\\0&1&-16/14&-36/14\\0&0&96/14&-288/14\end{array}\right]

Finally, to remove the zeros from all rows in the third column outside of the third row, we can multiply the third row by (16/96) and adding it to the second row as well as multiplying the third row by (-10/96) and adding it to the first row. This results in

\left[\begin{array}{cccc}1&0&0&-5\\0&1&0&-6\\0&0&96/14&-288/14\end{array}\right]

We can then divide the third row by -96/14 to reach the desired third column, making the reduced row echelon form of the matrix

\left[\begin{array}{cccc}1&0&0&-5\\0&1&0&-6\\0&0&1&-3\end{array}\right]

Therefore,

x=-5

y=-6

z=-3

* we could also switch the second and third rows here to make the process a little simpler

3 0
3 years ago
Other questions:
  • The difference of twice a number G and 10 is 24.<br><br> Please help me as I'm stumped! Thank you!
    13·2 answers
  • How many possible rock paper scissors games are there?
    11·1 answer
  • Someone please help me
    14·2 answers
  • Every day, Bert spends an hour commuting to and from his office, driving at an average speed of 50 mph and taking the same route
    14·1 answer
  • The fraction 6/100 can be written as which decimal
    10·1 answer
  • PLEASE HELP! NO ONE WANTS TO HELP ME :( the person who would help me is the nicest.
    11·2 answers
  • Select the numbers that have a factor of 5. Mark all that apply.
    5·1 answer
  • 2x+5y =-20, 2x-3y=28
    8·2 answers
  • Find the two square roots of the number.<br><br> 144
    11·2 answers
  • Find the measure of the indicated angle to the nearest degree.
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!