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alexandr1967 [171]
4 years ago
11

A clever inventor claims to be able to make an electric car that makes its own electricity and never needs gas. The inventor cla

ims that as the car moves, the wind generated by the motion spins a propeller. The propeller turns a generator that makes electricity to power the car. Do you believe this car would work? Why or why not? (Hint: Think about conservation of energy.)
Physics
1 answer:
sergeinik [125]4 years ago
4 0

Answer:

Yes, it would work.

Explanation:

From Flehmings left hand rule, current can be generated when a coil cuts the magnetic field of a powerful magnet. Thus, the spin of properller turns a generator thereby converts motion to electrical energy.

The major challenge would be how to set the car in motion when at rest. But this can be solved by energy consrvation process. The law of conservation of energy states that energy cannot be created or destoyed, but transformed from one form to another. Thus, there would be mechanism having a device called an inverter which stores electric energy when the vehicle is in motion. This regenerates the required initial energy to set the electric car in motion when at rest or stops.

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A wave pulse travels along a string at a speed of 200 cm/s. What will be the speed if:
34kurt

Answer:

a) v_f = \sqrt{\frac{2TL}{m}} = \sqrt{2} v = \sqrt{2}2m/s =2.83 m/s

The velocity increase by a factor of \sqrt{2}

b) v_f = \sqrt{\frac{TL}{4m}} = \frac{1}{2} v = \frac{1}{2} *2m/s =1 m/s

The velocity decrease by a factor of 2.

c) v_f = \sqrt{\frac{4TL}{m}} = 2} v = 2 *2m/s =4m/s

The velocity increase by a factor of 2

d) v_f = \sqrt{\frac{4TL}{4m}} = v = 2m/s

The velocity not changes.

Explanation:

For this case we know that the velocity is v = 200 cm/s = 2m/s

v_f represent the final velocity after the changes specified,

Part a

The formula for the speed of a wave in a string is given by:

v = \sqrt{\frac{T}{\rho}}

And the linear density is defined as:

\rho = \frac{m}{L}

And if we replace this we got:

v = \sqrt{\frac{TL}{m}}

If the tension mass is doubled we have this:

v_f = \sqrt{\frac{2TL}{m}} = \sqrt{2} v = \sqrt{2}2m/s =2.83 m/s

The velocity increase by a factor of \sqrt{2}

Part b

If we mass is quadrupled we have this:

v_f = \sqrt{\frac{TL}{4m}} = \frac{1}{2} v = \frac{1}{2} *2m/s =1 m/s

The velocity decrease by a factor of 2.

Part c

If the length is quadrupled we have this:

v_f = \sqrt{\frac{4TL}{m}} = 2} v = 2 *2m/s =4m/s

The velocity increase by a factor of 2

Part d

For this case we know that the mass and the length are both quadrupled and we got:

v_f = \sqrt{\frac{4TL}{4m}} = v = 2m/s

The velocity not changes.

7 0
3 years ago
Why do functionalists argue that the incest taboo is a nearly universal norm?
katrin [286]
The most appropriate answer is C. the incest taboo facilitates the socialization of children and avoids role confusion. 
According to functionalism; the family performs several essential functions fpr society. It socializes children, it provides emotional and practical support for its members, it helps regulate sexual activity and sexual reproduction, and it provides its members with a social identity.
6 0
3 years ago
An athlete does one push-up. In the process, she moves half of her body weight, 250 newtons, a distance of 20 centimeters. This
s2008m [1.1K]
We know that an athlete moves half of her body weight 250 N a distance of 20 cm.
So:  F = 250 N,  d = 20 cm = 0.2 m
The work formula:
W = F * d
W = 250 N * 0.2 m
W = 50 J
Answer: Her work after one push-up is 50 J.
6 0
3 years ago
What rule should be used to transform a table of data to represent the
adoni [48]

Answer:

Multiply the x values with -1.

Explanation:

By multiplying the numbers by one, you are changing them to be the opposite of their original state.

You multiply the numbers that are in the x-value column because you are reflecting the image over the y-axis.

<em>Hope this helped and good luck!</em>

4 0
3 years ago
Two charged particles are a distance of 1.72 m from each other. One of the particles has a charge of 7.03 nC, and the other has
MaRussiya [10]

A. The magnitude (in N) of the electric force that one particle exerts on the other is 8.60×10⁻⁸ N

B. The force is repulsive

<h3>A. How to determine the magnitude of the electric force</h3>

From the question given above, the following data were obtained:

  • Charge 1 (q₁) = 7.03 nC = 7.03×10¯⁹ C
  • Charge 2 (q₂) = 4.02 nC = 4.02×10¯⁹ C
  • Electric constant (K) = 9×10⁹ Nm²/C²
  • Distance apart (r) = 1.72 m
  • Force (F) =?

The magnitude of the electric force can be obtained by using the Coulomb's law equation as shown below:

F = Kq₁q₂ / r²

F = (9×10⁹ × 7.03×10¯⁹ × 4.02×10¯⁹) / (1.72)²

F = 8.60×10⁻⁸ N

<h3>B. How to determine whether the force is attractive or repulsive</h3>

From the question given, we were told that:

  • Charge 1 (q₁) = 7.03 nC
  • Charge 2 (q₂) = 4.02 nC

Since both charge are positive, then the force attraction between them is repulsive as like charges repels and unlike charges attracts

Learn more about Coulomb's law:

brainly.com/question/506926

#SPJ1

4 0
2 years ago
Read 2 more answers
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