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Valentin [98]
3 years ago
13

a ball of mass 100g falls from a height of 5m and rebounds to a height of 3m . calculate the energy lost . (g=10ms-2)​

Physics
1 answer:
scZoUnD [109]3 years ago
6 0

Explanation:

use the explanation above

Hope it's clear

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What kind of error would result if you read the liquid volume where the liquid touches the wall of the cylinder rather than at t
shutvik [7]
You would get a wrong calculaton which if you are doing an experiment it can mess with the results

7 0
3 years ago
Given: G = 6.67259 × 10−11 N m2 /kg2 . A 438 kg geosynchronous satellite orbits a planet similar to Earth at a radius 1.94 × 105
photoshop1234 [79]

Answer:

449.37412 N

Explanation:

G = Gravitational constant = 6.67259 × 10⁻¹¹ m³/kgs²

m = Mass of satellite = 438 kg

M = Mass of planet

T = Time period of the satellite = 24 h

r = Radius of planet = 1.94\times 10^8\ m

The time period of the satellite is given by

T=2\pi\sqrt{\frac{r^3}{GM}}\\\Rightarrow M=4\pi^2\frac{r^3}{T^2G}\\\Rightarrow M=4\pi^2\times \frac{(1.94\times 10^8)^3}{(24\times 3600)^2\times 6.67259\times 10^{-11}}\\\Rightarrow M=5.78686\times 10^{26}\ kg

The gravitational force is given by

F=G\frac{Mm}{r^2}\\\Rightarrow F=6.67259\times 10^{-11}\times \frac{5.78686\times 10^{26}\times 438}{(1.94\times 10^8)^2}\\\Rightarrow F=449.37412\ N

The force acting on this satellite is 449.37412 N

3 0
3 years ago
A block of mass m=3.0 kg is pushed down a 50° incline surface with a force of magnitude F=40 N.
Sauron [17]

Answer:

I really don't know but please if you find the correct answer tell me because I'm eager to know

7 0
3 years ago
PLS HELP WITH STEPS I'LL MARK U BRAINLISTT
Viktor [21]
35 m because if you count the space he took back it’s equivalent to 15 meters and so 20 + 15 = 35
4 0
3 years ago
Read 2 more answers
In unit-vector notation, what is the net torque about the origin on a flea located at coordinates (-2.0, 4.0 m, -1.0 m) when for
kifflom [539]

Answer:

Torque, \tau=-21i-8j+10k

Explanation:

Given that,

Coordinates, r=(-2i+4j-k)\ m

Force acting on the flea, F=(0i-5j-4k)\ N

Let \tau is the net torque about the origin on a flea. It is given by the following formula :

\tau=r\times F

\tau=(-2i+4j-k)\times (0i-5j-4k)

\tau=\begin{pmatrix}-21&-8&10\end{pmatrix}

\tau=-21i-8j+10k

So, the net torque about the origin on a flea is -21i-8j+10k. Hence, this is the required solution.

6 0
3 years ago
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