Question

Determine the electric field (in N/C) required to give the maximum possible deviation angle. (Enter the magnitude.)

Answer 1

Answer:

Maximum angle = 3.43⁰

Explanation:

Say that you are given the following information:

vertical distance between the charge plate = 0.03 m

length of the plate = 0.5 m

velocity of the electrons = 5 × 10⁶ ms⁻¹

the maximum angle is given by the formula:

$tan\theta _{max} = \frac{d}{l}$

where d = vertical distance between the charge plate

l = length of the plate

substituting the values l and d gives:

$tan\theta _{max} = \frac{0.03}{0.5}$

maximum angle, $\theta _{max} = \frac{0.03}{0.5}$

                                      $\theta _{max} = tan^{-1} (\frac{0.03}{0.5} )$

                                               =  3.43⁰