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3 years ago

Ben and Arthur teach us that you have to start investing by age thirty.

1 answer:

6 0

Who is Ben and Arthur? I’m sorry, I’m not with the trends. And investing early is important, coming for a young entrepreneur like myself.

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In a right triangle ΔABC, the length of leg AC = 5 ft and the hypotenuse AB = 13 ft. Find the length of the angle bisector of an

Sauron [17]

Answer: the length of the angle bisector of angle ∠A is 6 ft

Step-by-step explanation:

The diagram of the right angle triangle ABC is shown in the attached photo

Looking at triangle ABC,

cos θ = adjacent side/hypotenuse side

cos θ = 5/13 = 0.3846

θ = 67.38 degrees

The bisector of an angle divides it into two equal halves. The bisector is represented by line AD.

θ/2 = 67.38/2 = 33.69 degrees

Therefore,

Cos 33.69 = 5/AD

AD × Cos 33.69 = 5

AD = 5/Cos 33.69 = 5/0.832

AD = 6 ft

3 0

3 years ago

What is the fraction in simplest form?<br>- 14<br> ____<br> 16

elena55 [62]

Answer: -7/8

Step-by-step explanation:

16/2 = 8

14/2 = 7

Then its negative because its still negative.

3 0

3 years ago

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Prepare journal entries

lara31 [8.8K]

Answer:

Step-by-step explanation:

4 0

3 years ago

For the function given state the period f(t) =6sin(3t-pi/6)-1

lapo4ka [179]

$\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\
% function transformations for trigonometric functions
\begin{array}{rllll}
% left side templates
f(x)=&{{ A}}sin({{ B}}x+{{ C}})+{{ D}}
\\\\
f(x)=&{{ A}}cos({{ B}}x+{{ C}})+{{ D}}\\\\
f(x)=&{{ A}}tan({{ B}}x+{{ C}})+{{ D}}

\end{array}$

$\bf \begin{array}{llll}
% right side info
\bullet \textit{ stretches or shrinks}\\
\quad \textit{horizontally by amplitude } |{{ A}}|\\\\
\bullet \textit{ horizontal shift by }\frac{{{ C}}}{{{ B}}}\\
\qquad if\ \frac{{{ C}}}{{{ B}}}\textit{ is negative, to the right}\\\\
\qquad if\ \frac{{{ C}}}{{{ B}}}\textit{ is positive, to the left}\\\\
\end{array}$

$\bf \begin{array}{llll}


\bullet \textit{vertical shift by }{{ D}}\\
\qquad if\ {{ D}}\textit{ is negative, downwards}\\\\
\qquad if\ {{ D}}\textit{ is positive, upwards}\\\\
\bullet \textit{function period or frequency}\\
\qquad \frac{2\pi }{{{ B}}}\ for\ cos(\theta),\ sin(\theta),\ sec(\theta),\ csc(\theta)\\\\
\qquad \frac{\pi }{{{ B}}}\ for\ tan(\theta),\ cot(\theta)
\end{array}$

now, with that template in mind, let's take a peek at yours

$\bf \begin{array}{lllcclll}
f(t)=&6sin(&3t&-\frac{\pi }{6})&-1\\
&\uparrow &\uparrow &\uparrow &\uparrow \\
&A&B&C&D
\end{array}\\\\
-----------------------------\\\\
period\qquad \cfrac{2\pi }{B}\iff\cfrac{2\pi }{3}$

8 0

3 years ago

Which is greater 1 1/10 or 1 1/12

RoseWind [281]

1 1/10
........................

3 0

3 years ago

Read 2 more answers