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arsen [322]
3 years ago
14

(-∞-)help me help me help me help me help me help me help me help me help me help me help me help me help me help me help me hel

p me help me help me

Mathematics
2 answers:
Akimi4 [234]3 years ago
7 0

Answer:

-9

Step-by-step explanation:

Amanda [17]3 years ago
6 0

Answer: -9

Step-by-step explanation: its just like adding positive numbers, just with negative signs

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I feel like being nice, first two answers will get 50 points, the first one to answer gets the brainliest.. (You can put any ans
garik1379 [7]

Answer:

you are so so nice, to give away such big points...may God bless you and stay home and be safe :)

Step-by-step explanation:

1 x 1 is obviously 1

any number multiplied by one that answers that number is the same number.

8 0
3 years ago
Good afternoon please help! Geometry! Thank You!! Brainliest!
Step2247 [10]

Answer:

first one should be SAS

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3 0
2 years ago
Y is inversely proportional to the square of (x + 2).<br>When x = 3, y = 2.<br>Find y when x = 8.​
VikaD [51]

Answer:

y = k/(x+2) squared

substitute y and x to find the value of k.

k =50

nxt used the value of k with same formula:.

y= 50/ (8+2) squared

y =1/2

6 0
2 years ago
Please help me on this!
Blizzard [7]
1,2, and 6 are all no’s but everything else is yes I believe
5 0
2 years ago
Solve.
Nikitich [7]
The answer is C: 10\text{ }^1/_2. Here are the details:

\text{Equation:}\\ 6\text{ }^1/_3+10\text{ }^1/_2\stackrel{?}{=}26\text{ }^1/_6\\ \\ \text{Start with the integers.}\\ 6+10=16\stackrel{?}{=}26\text{ }^1/_6\\ \\ \text{...then with the fractions, but rewrite them first to make it easier.}\\ ^1/_3+\text{ }^1/_2\stackrel{\text{rewrite}}{\to}\text{ }^2/_6+\text{ }^3/_6=\text{ }^5/_6\stackrel{?}{=}26\text{ }^1/_6\\&#10;\\&#10;\text{Add 'em up!}\\&#10;16\text{ }^5/_6

\text{Equation:}\\&#10;16\text{ }^5/_6+3\text{ }^5/_6\stackrel{?}{=}26\text{ }^1/_6\\&#10;\\&#10;\text{Start with the integers.}\\&#10;16+3=19\stackrel{?}{=}26\text{ }^1/_6\\&#10;\\&#10;\text{...then with the fractions, but rewrite them first to make it easier.}\\&#10;^5/_6+\text{ }^5/_6=\text{ }^{10}/_6\stackrel{\text{rewrite}}{\to}\text{ }^5/_3\stackrel{\text{rewrite}}{\to}1\text{ }^2/_3\stackrel{?}{=}26\text{ }^1/_6\\&#10;\\&#10;\text{Add 'em up!}\\&#10;20\text{ }^2/_3

\text{Last equation:}\\ 20\text{ }^2/_3+5\text{ }^1/_2\stackrel{?}{=}26\text{ }^1/_6\\ \\ \text{Start with the integers.}\\ 20+5=25\stackrel{?}{=}26\text{ }^1/_6\\ \\ \text{...then with the fractions, but rewrite them first to make it easier.}\\ ^2/_3+\text{ }^1/_2\stackrel{\text{rewrite}}{\to}\text{ }^4/_6+\text{ }^3/_6=\text{ }^7/_6\stackrel{\text{rewrite}}{\to}1\text{ }^1/_6\stackrel{?}{=}26\text{ }^1/_6\\&#10;\\&#10;\text{Add the integer and fraction together.}\\&#10;25+1\text{ }^1/_6\stackrel{?}{=}26\text{ }^1/_6

26\text{ }^1/_6\stackrel{\checkmark}{=}26\text{ }^1/_6
5 0
3 years ago
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