Which model represents 0.69 divided by 3 I need this ASAP DUE IN 5 minutes

PLEASE HELP

Tems11 [23]

QUESTION A

The given multiplication problem is

$\frac{39}{64} \times \frac{8}{13}$

Factor each term to obtain;

$\frac{13\times 3}{8\times8} \times \frac{8}{13}$

Cancel out the common factors to obtain;

$\frac{1\times 3}{8\times1} \times \frac{1}{1}$

Simplify to get;

$\frac{3}{8}$

QUESTION B

The given multiplication problem is

$\frac{2}{3}\times \frac{1}{5}\times \frac{4}{7}$

This the same as

$\frac{2\times 1\times 4}{3\times 5\times 7}$

This simplifies to;

$\frac{8}{105}$

QUESTION C

The given problem is

$\frac{3}{5}\times \frac{10}{12} \times \frac{1}{2}$

This is the same as

$\frac{3}{5}\times \frac{5}{6} \times \frac{1}{2}$

$=\frac{1}{1}\times \frac{1}{2} \times \frac{1}{2}$

This simplifies to

$=\frac{1}{4}$

QUESTION D.

The given expression is

$\frac{4}{9}\times 54$

Factor the 54 to obtain;

$\frac{4}{9}\times 9\times 6$

Cancel the common factors to get;

$\frac{4}{1}\times 1\times 6$

This simplifies to;

$=24$

QUESTION E

The given problem is

$20\times 3\frac{1}{5}$

Convert the mixed numbers to improper fraction to obtain;

$=20\times \frac{16}{5}$

$=4\times5 \times \frac{16}{5}$

Cancel the common factors to get;

$=4\times1 \times \frac{16}{1}$

$=64$

QUESTION F

The multiplication problem is

$11 \times 2 \frac{7}{11}$

Convert the mixed numbers to improper fractions to obtain;

$11 \times \frac{29}{11}$

Cancel out the common factors to get;

$=1 \times \frac{29}{1}$

Simplify;

$=29$

QUESTION G

The given problem is

$5\frac{1}{3}\times 5\frac{1}{8}$

Convert to improper fractions;

$=\frac{16}{3}\times \frac{41}{8}$

Cancel out the common factors to get;

$=\frac{2}{3}\times \frac{41}{1}$

$=\frac{82}{3}$

Convert back to mixed numbers

$=27\frac{1}{3}$

QUESTION H

The given expression is

$10\frac{2}{3} \times 1\frac{3}{8}$

Convert to improper fraction to get;

$\frac{32}{3} \times \frac{11}{8}$

Cancel common factors to get;

$=\frac{4}{3} \times \frac{11}{1}$

Simplify

$=\frac{44}{3}$

Convert back to mixed numbers;

$=14\frac{2}{3}$

7 0

3 years ago

The dimensions of Rectangle A are 6 times the dimensions of Rectangle B. How do the areas of the Rectangles compare

Vedmedyk [2.9K]

The area of Rectangle A will always be 36 times the area of Rectangle B.

For example:
If Rectangle B has length 1 and width 2, Rectangle A will have length 6 and width 12. By multiplying, Rectangle A will have an area of 72 and B 2. Divide the two numbers and you will have 36.

Feel free to try with other numbers if you want to test it out.

3 0

4 years ago

A pilot can see the runway she is about to land on directly ahead. when looking at each end of the runway the angles of depressi

pogonyaev

We will use trigonometry:
tan 45° = 1500 / x
1 = 1500 / x
x = 1500 ft
tan 42° = 1500 / y
0.9 = 1500 / y
y = 1500 : 0.9
y = 1666.67 ft
L = y - x ( where L is the length of the runway )
L = 1666.67 - 1500 = 166.67 ft.

8 0

4 years ago

How are the triangles congruent? A) not congruent B) ASA C) SAS D) AAS

tatiyna

Answer:

A) not congruent. You only know one side and one angle to be congruent.

Step-by-step explanation:

7 0

3 years ago

What is the domain of f(x) = 2^x?

hammer [34]

The given function has no undefined points nor domain constraint. Thus, the domain is: $-\infty \: < x < \infty$ .

<h3>Domain and Range</h3>

The domain of a function is the set of input values for which the function is real and defined. In the other words, when you define the domain, you are indicating for which values x the function is real and defined. An example, there is a restriction for the domain of fractions. The variable x in the denominator should be different of zero.

While the domain is related to the values of x, the range is related to the possible values of y that the function can have.

In this question, the function $2^x$ has no undefined points nor domain constraint. Therefore, the domain is: $-\infty \: < x < \infty$

Learn more about the domain here:

brainly.com/question/10197594

#SPJ1

3 0

2 years ago