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3 years ago

I need help with these questions please.

Mathematics

1 answer:

astraxan [27]3 years ago

8 0

Answer:

A'(0,1), B'(1,0) and the lines are parallel
dilation factor is 2
A(-2,0), B(2,0); twice the length

Step-by-step explanation:

1. Whenever dilation is about the origin, the dilation factor affects each coordinate individually. When the dilation factor is 1/2, each coordinate of the image is 1/2 the coordinate of the pre-image:

A(0, 2) ⇒ A'(0, 1)

B(2, 0) ⇒ B'(1, 0)

2. The above description works in reverse, as well. If the dilation factor is 1/2, the pre-image has coordinate values twice those of the image. Dilation does not change directions or angles, so any dilated lines are parallel.

3. The center of dilation is an invariant point: it does not move. As in the second problem, the pre-image is twice the size of the image when the scale factor is 1/2.

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5.) Evaluate the function. f(x)=8x+9 for f(5). Show your work and write your

irina1246 [14]

Answer:

Step-by-step explanation:

f(5)=8×5+9=40+9=49

7 0

3 years ago

Assuming that the population is normally distributed, construct a 9090% confidence interval for the population mean for each o

jasenka [17]

Given:

Set A: 1 4 4 4 5 5 5 8

Mean: 4.5

Standard dev: 1.9

Set B:

Mean: 4.5

Standard dev: 2.45

% = 90

Set A:

Standard Error, SE = s/ √n = 1.9/√8 = 0.67

Degrees of freedom = n - 1 = 8 -1 = 7

t- score = 1.89457861

Width of the confidence interval = t * SE = 1.89457861* 0.67 = 1.272685913

Lower Limit of the confidence interval = x-bar - width = 4.5 - 1.272685913 = 3.23

Upper Limit of the confidence interval = x-bar + width = 4.5 + 1.272685913 = 5.77

The 90% confidence interval is [3.23, 5.77]

Set B:

Standard Error, SE = s/ √n = 2.45/√8 = 0.87

Degrees of freedom = n - 1 = 8 -1 = 7

t- Score = 1.89457861

Width of the confidence interval = t * SE = 1.89457861* 0.87 = 1.641094994

Lower Limit of the confidence interval = x-bar - width = 4.5 - 1.641094994 = 2.86

Upper Limit of the confidence interval = x-bar + width = 4.5 + 1.641094994 = 6.14

The 90% confidence interval is [2.86, 6.14]

We can obviously see that sample B has more variation in the scores than sample A. The fact that the standard deviation is 2.45 for B and 1.9 for A). Therefore, they yield dissimilar confidence intervals even though they have the same mean and range.

6 0

3 years ago

A farmer has 15 boxes of eggs

Yuki888 [10]

A farmer has 15 boxes of eggs and there are 6 eggs in each box. Therefore it will be part to whole. The bigger number is always the whole. 6:15 is the ratio.

8 0

2 years ago

Look at the question below.

sweet-ann [11.9K]

Answer: bottom left

4x+2y+15

Step-by-step explanation:

3x + x=4x

5 + 10= 15

2y=2y

4x+2y+15

6 0

3 years ago

Read 2 more answers

A can in the shape of a right cylinder is filled with 10W-40 oil. The weight of 10W-40 oil is 0.857 gram per cubic centimeter. I

Leya [2.2K]

To solve this, we have to find the volume of the cylinder first. The formula to be used is $V = \pi r^{2} h$

Given:V= ?r= 6cmh= 10cm
Solution: $V = \pi r^{2} h$
V= (3.14)(6cm) $^{2}$ x 10cmV= (3.14)( $36cm^{2}$ ) x 10cmV= ( $113.04cm^{2}$ ) x 10cmV= 1130.4cm^3
Finding the volume of the cylinder, we can now solve what the weight of the oil is. Using the formula of density, Density = mass/volume, we can derive a formula to get the weight.
Given:Density = 0.857 gm/cm^3Volume = 1130.4 cm^3
Solution:weight = density x volumew= (0.857 gm/cm^3) (1130.4cm^3)w= 968.7528 gm
The weight of the oil is 968.75 gm.

5 0

3 years ago