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Area of ABC : AB*AC/2
the maximum of the parabola is reached at x=-4/(2*(-1))=2 hence A is at (2,0) and B is at (2,(-2)^2+4*2+C)=(2,12+C)
C is the second root (x-intersect), which we can find :
determinant1 : D=16-4*(-1)*C=4(4+C) thus the second root is at x=
Hence the area of the triangle is
hence 
.
We remark that
Hence 4+C=16 thus C=12
the maximum of the parabola is reached at x=-4/(2*(-1))=2 hence A is at (2,0) and B is at (2,(-2)^2+4*2+C)=(2,12+C)
C is the second root (x-intersect), which we can find :
determinant1 : D=16-4*(-1)*C=4(4+C) thus the second root is at x=
Hence the area of the triangle is
We remark that
Hence 4+C=16 thus C=12
The problem solved correctly as a single logarithm is
From the question, we are to simplify the given logarithm
The given logarithm is
From the subtraction law of logarithm, we have that
Thus,
The error in the solution was instead of multiplying, a was supposed to be divided by b
The correct solution is
Simplifying further
Hence, the problem solved correctly as a single logarithm is
Learn more on Simplifying logarithms here: brainly.com/question/247340
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