Answer:
95% confidence for µ, the average number of times a horse races
(12.493 , 18.107)
Step-by-step explanation:
<u>Explanation</u>:-
The veterinarian finds that the average number of races a horse enters is 15.3
The mean of the sample x⁻ = 15.3
Given standard deviation of the sample 'S' = 6.8
Given sample size 'n' = 25
Degrees of freedom = n-1 =25-1 =24
The tabulated value 't' = 2.064 at two tailed test 0.95 level of significance
<u> 95% confidence for µ, the average number of times a horse races</u>
<u></u>
<u></u>
<u></u>
<u></u>
(15.3 - 2.80704 ,15.3 +2.80704)
(12.493 , 18.107)
<u>Conclusion</u>:-
95% confidence for µ, the average number of times a horse races
(12.493 , 18.107)
It was given that
1 gal = 20 lbs of CO2
1 gal = 25 miles distance
Thus,
15000 miles/year ( 1 gal / 25 miles ) ( 20 lbs CO2 / 1 gal ) = 12000 CO2
<span>If Harry drives 15,000 miles per year, his vehicle will add 12000 pounds of CO2 to the atmosphere.</span>
Time = distance / speed
= 95/ 105 = 0.905 hours or about 54.3 minutes or 54 minutes 17 seconds
Answer:
12 percent
Step-by-step explanation:
24 by 100 0f 50
24 ×50=1200
1200÷100 is 12
Answer:
Isolate the variable by dividing each side by factors that don't contain the variable.
Exact Form:
x
=
1
3
Decimal Form:
0.3
this is the first one I'm not to good with area