Answer:
maximum height of the arrow will be 408 m
Step-by-step explanation:
We have given the function of height as 
We know that first derivative of height will be velocity
So first derivative of height
We know that at maximum height velocity will be zero
t = 5 sec
Sp arrow will be at maximum height at t = 5 sec
So height at t = 5 sec will be
So maximum height of the arrow will be 408 m
Answer:
45°, 45°, 90°
Step-by-step explanation:
Find the vectors to represent each sides
AB =<3-1, 6-0>=<2,6>
AC = < -1-1, 4 - 0 > = < -2, 4>
Magnitude of the vectors
AB = √(2²+6²) = 6.32
AC = √ ((-2)² + 4²) = 4.47
cosθ = vector of AB × vector AC / ( Product of the magnitude of AB and AC) = 2 × (-2) + (6×4)/ (6.32×4.47) = 20 / 28.2504
θ = arcos(20 / 28.2504 ) approx = 45°
Magnitude of the vectors
BA =<1-3,0-6>=<-2,-6>
BC =<-1-3,4-6>=<-4,-2>
Magnitude of the vectors equals
BA = √((-2)² + (-6)²) = 6.325
BC = √((-4)² + (-2)²) = 4.4721
cosθ = (-2×-4) + (-6 ×-2) / (6.325 × 4.4721) = 20 / 28.286
θ = arcos (20 / 28.286 ) = 45°
Magnitude of the vectors
CB =<3--1, 6-4>=<4,2>
CA=<1--1,0-4>=<2,-4>
Magnitude of the vector =
CB = √(4² + 2²) = 4.4721
CA = √(2² + (-4)²) = 4.4721
cosθ = (4×2) + (2×-4) / (4.4721×4.4721) = 0
θ = arcos 0 = 90°
They should be eggshell. The color would look good in the hotel rooms.
