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2 years ago

What does 6/1 equal in its simplest form

Mathematics

1 answer:

TEA [102]2 years ago

3 0

6/1 in simplest form is 6 because 6 divided by 1 is 6.

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Can someone solve what is n/n^3

emmasim [6.3K]

Answer:

Alex = No B.

Step-by-step explanation:

1) Use Quotient Rule: $\frac{x^{a} }{x^{b} } =x^{a-b}$

$n^{1-3}$

2) Simplify 1 - 3 = 2

$n^{-2}$

3) Use Negative Power Rule: $x^{-a} =\frac{1}{x^{a} }$

$\frac{1}{n^{2} }$

3 0

1 year ago

Help!!! Look at the image below.. X= 8? 9? 10?

Korolek [52]

I think it is 10 lol sorry I’m not sure

8 0

2 years ago

given that BD is the median of ABD and that ABD is isosceles congruence postulate SSS can be used to prove which of the followin

Alja [10]

It is given in the question that

BD is the median. So it divides the opposite sides in two equal parts .

Therefore in triangles BAD and BCD,

AB and AC are congruent because of isosceles triangle.

AD and CD are congruent because of the median BD.

And BD and BD are congruent .

So the two triangles are congruent by SSS and the correct option is the first option .

3 0

2 years ago

Read 2 more answers

(cotx+cscx)/(sinx+tanx)

Butoxors [25]

Answer: $\bold{\dfrac{cot(x)}{sin(x)}}$

<u>Step-by-step explanation:</u>

Convert everything to "sin" and "cos" and then cancel out the common factors.

$\dfrac{cot(x)+csc(x)}{sin(x)+tan(x)}\\\\\\\bigg(\dfrac{cos(x)}{sin(x)}+\dfrac{1}{sin(x)}\bigg)\div\bigg(\dfrac{sin(x)}{1}+\dfrac{sin(x)}{cos(x)}\bigg)\\\\\\\bigg(\dfrac{cos(x)}{sin(x)}+\dfrac{1}{sin(x)}\bigg)\div\bigg[\dfrac{sin(x)}{1}\bigg(\dfrac{cos(x)}{cos(x)}\bigg)+\dfrac{sin(x)}{cos(x)}\bigg]\\\\\\\bigg(\dfrac{cos(x)}{sin(x)}+\dfrac{1}{sin(x)}\bigg)\div\bigg(\dfrac{sin(x)cos(x)}{cos(x)}+\dfrac{sin(x)}{cos(x)}\bigg)$

$\text{Simplify:}\\\\\bigg(\dfrac{cos(x)+1}{sin(x)}\bigg)\div\bigg(\dfrac{sin(x)cos(x)+sin(x)}{cos(x)}\bigg)\\\\\\\text{Multiply by the reciprocal (fraction rules)}:\\\\\bigg(\dfrac{cos(x)+1}{sin(x)}\bigg)\times\bigg(\dfrac{cos(x)}{sin(x)cos(x)+sin(x)}\bigg)\\\\\\\text{Factor out the common term on the right side denominator}:\\\\\bigg(\dfrac{cos(x)+1}{sin(x)}\bigg)\times\bigg(\dfrac{cos(x)}{sin(x)(cos(x)+1)}\bigg)$

$\text{Cross out the common factor of (cos(x) + 1) from the top and bottom}:\\\\\bigg(\dfrac{1}{sin(x)}\bigg)\times\bigg(\dfrac{cos(x)}{sin(x)}\bigg)\\\\\\\bigg(\dfrac{1}{sin(x)}\bigg)\times cot(x)}\qquad \rightarrow \qquad \dfrac{cot(x)}{sin(x)}$

6 0

3 years ago

A farm stand sells apples pies and jars of applesauce. The table shows the number of apples needed to

Galina-37 [17]

Answer:

Step-by-step explanation:

3 0

2 years ago