There are total of 5 digits, of which we arrange 3 of them.
Therefore using permutations we can find total possible 3-number combinations.
5P3 = 5*4*3 = 60
To be greater than 600 means first digit must be 6. (1 possibility)
A number is even only if last digit is even, 2 or 4. (2 possibilities)
The 2nd digit then can only be 3,5, (2 or 4). (3 possibilities)
The total possible even 3-digit numbers greater than 600 is product of each digit's possibilities.
---> 1*3*2 = 6
Therefore probability is 6/60 = 1/10.
Answer:
a range of values such that the probability is C % that a rndomly selected data value is in that range
Step-by-step explanation:
complete question is:
Select the proper interpretation of a confidence interval for a mean at a confidence level of C % .
a range of values produced by a method such that C % of confidence intervals produced the same way contain the sample mean
a range of values such that the probability is C % that a randomly selected data value is in that range
a range of values that contains C % of the sample data in a very large number of samples of the same size
a range of values constructed using a procedure that will develop a range that contains the population mean C % of the time
a range of values such that the probability is C % that the population mean is in that range
According to the data of December 2017, the most poorest countries in the world are in Africa (Guinea, Somali, Mozambique, Burundi, Malawi, Liberia, Central African Republic, Niger), the most poorest is Central African Republic.
Its economic basically is dependent on diamonds export, the most of the diamonds is soled on the 'black' market, which allow to pass the taxes of government...
1/48
Since there is only 1 page labeled “3,” the probability of picking page 3 is 1/48.
