5/x^2-1^2 + 3/x+1
5/(x+1)(x-1) + 3/x+1
5+3(x-1)/(x+1)(x-1)
5+3x-3/(x+1)(x-1)
Final answer : 3x+2/(x+1)(x-1)
(3c+s)(100-20)/100=100 multiply both sides by 100
(3c+s)80=10000 divide both sides by 80
3c+s=125 subtract 3c from both sides...
s=125-3c....now let's look at the second situation...
(4c+2s)(100-40)/100=120 multiply both sides by 100
60(4c+2s)=12000 divide both sides by 60
4c+2s=200 divide both sides 2
2c+s=100 subtract 2c from both sides
s=100-2c, and from earlier we saw that s=125-3c, since s=s:
100-2c=125-3c add 3c to both sides
100+c=125 subtract 100 from both sides
c=25, and since s=100-2c
s=50
So cds cost $25.00 and sweatshirts cost $50.00
Answer:
it is 20% your welcome
Step-by-step explanation:
because when you divide 100 by 2 its 50 so its 20%
(cube root of 5) * sqrt(5)
--------------------------------- = ?
(cube root of 5^5)
This becomes easier if we switch to fractional exponents:
5^(1/3) * 5^(1/2) 5^(1/3 + 1/2) 5^(5/6)
------------------------ = --------------------- = ------------- = 5^[5/6 - 5/3]
[ 5^5 ]^(1/3) 5^(5/3) 5^(5/3)
Note that 5/6 - 5/3 = 5/6 - 10/6 = -5/6.
1
Thus, 5^[5/6 - 5/3] = 5^(-5/6) = --------------
5^(5/6)
That's the correct answer. But if you want to remove the fractional exponent from the denominator, do this:
1 5^(1/6) 5^(1/6)
---------- * ------------- = -------------- (ANSWER)
5^(5/6) 5^(1/6) 5
If you were at 54 on the number line you would have to cross zero and go an extra 13 steps to get to -13.
So we want the difference between 54 and -13 or 54- -13 which becomes 54+13 which is 67 - that is the range
