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mezya [45]
4 years ago
12

1. Why does Chaucer include both positive and negative representations of people from different estates in The Canterbury Tales?

Give one example of a positive representation and one example of a negative representation. Explain how each character shows either positive or negative traits. Your answer should be at least one paragraph.
English
2 answers:
Gwar [14]4 years ago
6 0

In the prologue of the "Canterbury Tales", peculiar characteristics of personality of the pilgrim characters, who are on their way to a shrine, are presented and described. The pilgrimage was a fine opportunity fro people from various social estates and ranks to intermingle and exchange in their tales the way of living of the class they belonged to. An example of a positive representation is the noble knight, who told a romance, "and he a worthy man / Who from the moment that he first began / To ride about the world, loved chivalry." A personification of courtly love and honor he was indeed. In contrast for instance with the Miller, who "was a janglere and a goliardeys, / And that was most of sinne and harlotryes." This coarse pilgrim told a fabliau, a genre about ordinary people opposite to the romance which depicted life at noble courts in fair kingdoms, to mock the Knight's story. Never in life would they have met, however, pilgrimage allowed their encountering and Chaucer was aware of the possibilities of the journey for people from different estates to interact.

mash [69]4 years ago
3 0
The fact that this has been posted multiple times defeats its purpose, but i'm pretty sure there is a correct answer on the other post.

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Answer:

The answer is: <u>False</u>

Explanation:

Rather than "maintenance" what actually needs; researching the discissusion topic, keeping the group on track and helping the group reach consensus is <u>"The task". </u>So it has to look like this:

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Fernando evaluated the expression below. StartFraction 5 (9 minus 5) over 2 EndFraction + (negative 2) (negative 5) + (negative
Juli2301 [7.4K]

Question:

Fernando evaluated the expression below.

\frac{5(9-5)}{2} + (-2)(-5) + (-3)^2 = \frac{5(4)}{2} -10 + 9 = \frac{20}{2} - 10 + 9 = 10 - 10 + 9 = 9

What was Fernando's error?

- Fernando evaluated the numerator of the fraction incorrectly.

- Fernando simplified 20/2 incorrectly.

- Fernando incorrectly found the product of –2 and –5.

- Fernando evaluated (-3)² incorrectly.

Answer:

- Fernando incorrectly found the product of –2 and –5.

Explanation:

Given

\frac{5(9-5)}{2} + (-2)(-5) + (-3)^2 = \frac{5(4)}{2} -10 + 9 = \frac{20}{2} - 10 + 9 = 10 - 10 + 9 = 9

Required

Spot the error

The error in this evaluation is the product of -2 and -5 at step 2

When a negative number (-2) is multiplied by a negative number (-5), the outcome of the multiplication is always a positive number (10).

So, the result of -2 * -5 is 10 but Fernando incorrectly calculated it as -10.

Solving the expression, correctly

\frac{5(9-5)}{2} + (-2)(-5) + (-3)^2 = \frac{5(4)}{2} + 10 + 9

\frac{5(9-5)}{2} + (-2)(-5) + (-3)^2 = \frac{20}{2} + 10 + 9

\frac{5(9-5)}{2} + (-2)(-5) + (-3)^2 = 10 + 10 + 9

\frac{5(9-5)}{2} + (-2)(-5) + (-3)^2 = 29

Hence, the actual result of the expression is 29 (not 9 as calculated by Fernando).

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