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3 years ago

Math be like 0-0????

Mathematics

1 answer:

pashok25 [27]3 years ago

5 0

Answer: A & C

<u>Step-by-step explanation:</u>

HL is Hypotenuse-Leg

A) the hypotenuse from ΔABC ≡ the hypotenuse from ΔFGH

a leg from ΔABC ≡ a leg from ΔFGH

Therefore HL Congruency Theorem can be used to prove ΔABC ≡ ΔFGH

B) a leg from ΔABC ≡ a leg from ΔFGH

the other leg from ΔABC ≡ the other leg from ΔFGH

Therefore LL (not HL) Congruency Theorem can be used.

C) the hypotenuse from ΔABC ≡ the hypotenuse from ΔFGH

at least one leg from ΔABC ≡ at least one leg from ΔFGH

Therefore HL Congruency Theorem can be used to prove ΔABC ≡ ΔFGH

D) an angle from ΔABC ≡ an angle from ΔFGH

the other angle from ΔABC ≡ the other angle from ΔFGH

AA cannot be used for congruence.

You might be interested in

In triangle DEF measurement angle D = 45 degrees meausrement angle E = 63 degrees and EF = 24 inches. What is DE to the nearest

alexandr1967 [171]

Since the angles add to 180°, angle F is 72°.

Using the law of sines,

DF/sin72° = 24/sin45°
x = 32.28

So, did you just guess at A?

This is just an answer from another website, but it should still work.

7 0

3 years ago

Read 2 more answers

Find all of the equilibrium solutions. Enter your answer as a list of ordered pairs (R,W), where R is the number of rabbits and

zloy xaker [14]

Answer:

$(0,0)$ $(4000,0)$ and $(500,79)$

Step-by-step explanation:

Given

See attachment for complete question

Required

Determine the equilibrium solutions

We have:

$\frac{dR}{dt} = 0.09R(1 - 0.00025R) - 0.001RW$

$\frac{dW}{dt} = -0.02W + 0.00004RW$

To solve this, we first equate $\frac{dR}{dt}$ and $\frac{dW}{dt}$ to 0.

So, we have:

$0.09R(1 - 0.00025R) - 0.001RW = 0$

$-0.02W + 0.00004RW = 0$

Factor out R in $0.09R(1 - 0.00025R) - 0.001RW = 0$

$R(0.09(1 - 0.00025R) - 0.001W) = 0$

Split

$R = 0$ or $0.09(1 - 0.00025R) - 0.001W = 0$

$R = 0$ or $0.09 - 2.25 * 10^{-5}R - 0.001W = 0$

Factor out W in $-0.02W + 0.00004RW = 0$

$W(-0.02 + 0.00004R) = 0$

Split

$W = 0$ or $-0.02 + 0.00004R = 0$

Solve for R

$-0.02 + 0.00004R = 0$

$0.00004R = 0.02$

Make R the subject

$R = \frac{0.02}{0.00004}$

$R = 500$

When $R = 500$ , we have:

$0.09 - 2.25 * 10^{-5}R - 0.001W = 0$

$0.09 -2.25 * 10^{-5} * 500 - 0.001W = 0$

$0.09 -0.01125 - 0.001W = 0$

$0.07875 - 0.001W = 0$

Collect like terms

$- 0.001W = -0.07875$

Solve for W

$W = \frac{-0.07875}{ - 0.001}$

$W = 78.75$

$W \approx 79$

$(R,W) \to (500,79)$

When $W = 0$ , we have:

$0.09 - 2.25 * 10^{-5}R - 0.001W = 0$

$0.09 - 2.25 * 10^{-5}R - 0.001*0 = 0$

$0.09 - 2.25 * 10^{-5}R = 0$

Collect like terms

$- 2.25 * 10^{-5}R = -0.09$

Solve for R

$R = \frac{-0.09}{- 2.25 * 10^{-5}}$

$R = 4000$

So, we have:

$(R,W) \to (4000,0)$

When $R =0$ , we have:

$-0.02W + 0.00004RW = 0$

$-0.02W + 0.00004W*0 = 0$

$-0.02W + 0 = 0$

$-0.02W = 0$

$W=0$

So, we have:

$(R,W) \to (0,0)$

Hence, the points of equilibrium are:

$(0,0)$ $(4000,0)$ and $(500,79)$

4 0

3 years ago

what is f(x) = 2x2 28x – 5 written in vertex form? f(x) = 2(x 7)2 – 19 f(x) = 2(x 7)2 – 103 f(x) = 2(x 14)2 – 14 f(x) = 2(x 14)2

polet [3.4K]

Hello,
++++++++++++++++++++++
Answer B
++++++++++++++++++++++

2x²+28x-5=2(x²+2*7x+49)-5-2*48
=2(x+7)²-103

++++++++++++++++++++++++++++++

4 0

3 years ago

Read 2 more answers

Find values of x and y for which ABCD must be a parallelogram. The diagram is not drawn to scale.

Arturiano [62]

ANSWER
$x=4, y=8$

EXPLANATION

If ABCD is a parallelogram, then

line AB is parallel to line DC .

This means that,

$(x + 2) \degree$
and

$(2x - 2) \degree$
are alternating angles.

Alternate angles are congruent.

This implies that,

$2x - 2 = x + 2$

We group like terms to obtain,

$2x - x = 2 + 2$

This simplifies to,

$x = 4$

Also, if ABCD is a parallelogram then,

BC is parallel to AD. This means that,

$5y - 8 = y + 24$

We group like terms to get,

$5y - y = 24 + 8$

This simplifies to,

$4y = 32$

We divide both side by 4 to get,

$y = 8$

6 0

3 years ago

Read 2 more answers

John works Monday to Friday. He buys his lunch on his way to work. Each day John buys a sandwich, a bottle of water and a bag of

kipiarov [429]

Complete question

Shop A _________________ shop B £3

Any sandwich - £2.85 ___ sandwich, water crisp

A bottle of water - 60p

A bag of crisp - 85p

Answer:

£6.50, John is incorrect

Step-by-step explanation:

Number of working days = 5 = number of days meal is purchased

Total cost per meal, shop A :

£(2.85 + 0.60 + 0.85) = £4.3

Total cost for the week = 4.3 * 5 = £21.50

Total cost per meal cost Shop B = £3

Total cost for the week = 3 * 5 = £15

Difference :

£21.50 - £15 = £6.50

Hence, Amount John saves by buying from shop B is £6.50

Numbe

4 0

2 years ago