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3 years ago

Simplify

Mathematics

2 answers:

tia_tia [17]3 years ago

5 0

Answer:

The correct answer is

. You would add the exponents of the numerator to get 47. Then you subtract the exponents to 4-2. When you have negative exponents then you move from the numerator or the denominator. So you move 4-2 to the bottom to get

Step-by-step explanation:

so the answer is C

Furkat [3]3 years ago

3 0

Answer:

i believe it should be c 1/4^2

Step-by-step explanation:

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How do u solve for x

Radda [10]

Sorry I can’t see the picture very well

7 0

3 years ago

Read 2 more answers

(2^8 . 5-5. 19^0)-2. <br> What is the product

Dennis_Churaev [7]

Answer:The final value of the expression is 149

2^8 . 5^-5 . 19^0)^-2

using PEMDAS

this = (2^8 * 1/5^5 * 1)^-2

= (5^5 / 2^8)^2

= 5^10 / 2^16

8 0

3 years ago

Ebony but a four year treasury note that pay the equivalent of 3.8% simple interest. She invested $3000 more in a 9 year bond e

Anastasy [175]

Treasury bond's invested amount is "$7000" and Bond's invested amount is "$10000",

Let,

The amount invested in treasury note will be = x
The amount invested in bond will be = (x + 3000)

then,

→ $\frac{x\times 4\times 3.8}{100} +\frac{(3000+x)\times 9\times 4.6}{100}=5204$

→ $\frac{15.2x}{100}+\frac{(3000+x)\times 41.4}{100} =5204$

→ $\frac{15.2x}{100} +\frac{124200+41.4x}{100} =5204$

→ $\frac{15.2 x+124200+41.4x}{100} = 5204$

→ $56.6x+124200=520400$

→ $56.6x=520400-124200$

→ $56.6x=396200$

→ $x = \frac{396200}{56.6}$

→ $= 7000$

Amount invested in bond will be:

= $x+3000$

= $7000+3000$

= $10000$

Thus the above is the correct answer.

Learn more:

brainly.com/question/14802140

8 0

3 years ago

The following data set represents the ACT scores for students in Mrs. Smith's collegescience class.18 32 16 2319 21 28 2922 30 1

nataly862011 [7]

Recall that in statistics, the mode is the value that appears most frequently in a set of data. You may find it useful to represent the data in statistical graphs such as dot plots or bar charts. In this case, we will use the following chart

As we can see from the image, The most frequently used numbers are 19 and 21. We are dealing with a bimodal data set. The mode is given by 19 and 21.