Answer:
f(1) = 16
Domain: 0 ≤ t ≤ 2
Step-by-step explanation:
Given
f(t) = -16t²+ 32t
Solving (a): f(1)
Substitute 1 for t in f(t)
f(t) =− 16t²+ 32t .
f(1) =− 16 * (1)²+ 32 * 1
f(1) = -16 * 1 + 32
f(1) = -16 + 32
f(1) = 16
Solving (b): The domain
The implication of the given parameter in (b) is that t ≤ 2.
Since t represents time, t can't be negative.
Hence, a reasonable domain is
0 ≤ t ≤ 2
Hello from MrBillDoesMath!
Answer: b
Discussion:
7b + 3 - 4b = 3 - 3(b+4) =>
7b + 3 - 4b = 3 - 3b -12 =>
(7b - 4b) + 3 = -3b - 9 =>
3b + 3 = -3b -9 => Add 9 to both sides
3b + 12 = -3b -9 + 9 =>
3b + 12 = -3b => ( add 3b to both sides)
6b + 12 = 0 => (subtract 12 from both sides)
6b = -12 =>
b = -12/6 = -2
Thank you,
MrB
Answer:
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