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2 years ago

The graph shows a line and two similar triangles.

Mathematics

1 answer:

jonny [76]2 years ago

6 0

The correct answer is y=3x please give me brainlest I hope this helps let me know if it’s correct or not

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I can’t figure out how to solve this for a. I’ve tried multiple ways but still have not come up with an answer.

abruzzese [7]

Answer:

a = 33

Step-by-step explanation:

IN a parallelogram consecutive angles are supplementary, thus

5a - 52 + 5a - 98 = 180, that is

10a - 150 = 180 ( add 150 to both sides )

10a = 330 ( divide both sides by 10 )

a = 33

8 0

3 years ago

Read 2 more answers

You start hiking at an elevation that is 80 meters below base camp. You increase your elevation by 42 meters. What is the new el

lina2011 [118]

Answer:

You are now 38 m below base camp.

Step-by-step explanation:

Consider the provided information.

You start hiking at an elevation that is 80 meters below base camp.

Now your initial location is 80 m below base camp, that can be represents as: -80

Now you increase your elevation by 42.

So you go up by 42.

In other words, you get the equation -80+42 = -38.

Since, a negative value is below the base camp, this means that you are now 38 m below base camp.

8 0

3 years ago

Confused on number 10. I put one solution, but I don’t know if it’s right. I got

velikii [3]

4(3x + 12) = -6(-8-2x)
12x + 48 = 48 +12x
12x + 18 = 12x + 48
0 = 0
answer is A. infinitely many solutions

4 0

3 years ago

The length of a rectangle is 5 metres less than twice the breadth. If the perimeter is 50 meters,find the length and breadth

MAXImum [283]

As per the given question, it is stated that the length of a rectangle is 5 m less than twice the breadth.

Assumption : Let us assume the length as "l" and width as "b". So,

$\twoheadrightarrow \quad\sf{ Length =2(Width)-5}$

$\twoheadrightarrow \quad\sf{ \ell=(2b-5) \; m}$

Also, we are given that the perimeter of the rectangle is 50 m. Basically, we need to apply here the formula of perimeter of rectangle which will act as a linear equation here.

$\\ \twoheadrightarrow \quad\sf{ Perimeter_{(Rectangle)} = 2(\ell +b) } \\$

l denotes length
b denotes breadth

$\\ \twoheadrightarrow \quad\sf{50= 2(2b-5+b)} \\$

$\\ \twoheadrightarrow \quad\sf{50= 2(3b-5)} \\$

$\\ \twoheadrightarrow \quad\sf{50= 6b - 10} \\$

$\\ \twoheadrightarrow \quad\sf{50+10= 6b} \\$

$\\ \twoheadrightarrow \quad\sf{60= 6b} \\$

$\\ \twoheadrightarrow \quad\sf{\cancel{\dfrac{60}{6}}=b} \\$

$\\ \twoheadrightarrow \quad\underline{\bf{10\; m = Width }} \\$

Now, finding the length. According to the question,

$\twoheadrightarrow \quad\sf{ \ell=(2b-5) \; m}$

$\twoheadrightarrow \quad\sf{ \ell=2(10)-5\; m}$

$\twoheadrightarrow \quad\sf{ \ell=20-5\; m}$

$\\ \twoheadrightarrow \quad\underline{\bf{15\; m = Length }} \\$

Therefore, length and breadth of the rectangle is 15 m and 10 m. 

7 0

3 years ago

Jodi built a rectangular sandbox for her daughter. The sandboxmeasures6 feet by 5feet by 1.2 feet. Jodi purchases 20cubic feet o

Mamont248 [21]

For this case, the first thing to do is to model the rectangular sandbox as a rectangular prism.

The volume of the prism is given by:

$V = w * l * h$

Where,

w: width
l: length
h: height

Therefore, replacing values we have:

$V = 6 * 5 * 1.2\\V = 36 ft ^ 3$

We observed that:

$36 ft ^ 3> 20 ft ^ 3$

Therefore, the sandbox is not completely filled.

Answer:

the sandbox will hold $36 ft ^ 3$ of sand

Jodi purchase is not enough sand to fill the sandbox to the top.

$36 ft ^ 3> 20 ft ^ 3$

8 0

3 years ago