Answer:
it is presented in chimpanzees
Use binomial distribution with p=0.25, n=5, x=2
P(X=x)=C(n,x)p^x (1-p)^(n-x)
P(X=2)=C(5,2) 0.25^2 0.75^(5-2)
=10*0.0625*0.421875
=0.26367
So the probability of 2 of 5 children having type-O blood from these parents is 0.26367.
Answer:
i would go with B and E
Explanation:
by the way u could just read it
The answer is "autotroph."
