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Marysya12 [62]
3 years ago
10

Classify the following unbalanced chemical reaction Fe(s) + Cl2(aq) = Fe2+(aq) + Cl-(aq)

Chemistry
1 answer:
svp [43]3 years ago
5 0

Answer:

3. Oxidation-Reduction Reaction

Explanation:

Fe(s) + Cl2(aq) = Fe2+(aq) + Cl-(aq)

Fe(s) -2e- ----> Fe2+(aq)  oxidation

Cl2(aq)  + 2e- -----> 2Cl-(aq)  reduction

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We first consider the gases that will be present in that sample.
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3 years ago
If a measurement is recorded as 1.2 cm, what is the smallest marking on the instrument?
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Be sure to answer all parts. Consider the following balanced redox reaction (do not include state of matter in your answers): 2C
timurjin [86]

Answer:

The specie which is oxidized is:- CrO_2^-

The specie which is reduced is:- ClO^-

Explanation:

Oxidation reaction is defined as the chemical reaction in which an atom looses its electrons. The oxidation number of the atom gets increased during this reaction.

X\rightarrow X^{n+}+ne^-

Reduction reaction is defined as the chemical reaction in which an atom gains electrons. The oxidation number of the atom gets reduced during this reaction.

X^{n+}+ne^-\rightarrow X

For the given chemical reaction:

2CrO_2^- + 6ClO^- + 2H_2O\rightarrow 2CrO_4^{2-} + 3Cl_2 + 4OH^-

The half cell reactions for the above reaction follows:

Oxidation half reaction:  CrO_2^- + 2H_2O + 4OH^-\rightarrow CrO_4^{2-} + 4H_2O + 3e^-

Reduction half reaction:  2ClO^- + 4H_2O + 2e^-\rightarrow Cl_2 + 2H_2O + 4OH^-

Thus, the specie which is oxidized is:- CrO_2^-

The specie which is reduced is:- ClO^-

8 0
4 years ago
What is the square root of 25
Sauron [17]

Answer:

5

Explanation:

because 5x5 = 25

and 25 ÷5= 5

4 0
4 years ago
Read 2 more answers
For elements in the third row of the periodic table and beyond, the octet rule is often not obeyed. a friend of yours says this
Rom4ik [11]

The reason that some of the elements of period three and beyond are steady in spite of not sticking to the octet rule is due to the fact of possessing the tendency of forming large size, and a tendency of making more than four bonds. For example, sulfur, it belongs to period 3 and is big enough to hold six fluorine atoms as can be seen in the molecule SF₆, while the second period of an element like nitrogen may not be big to comprise 6 fluorine atoms.  

The existence of unoccupied d orbitals are accessible for bonding for period 3 elements and beyond, the size plays a prime function than the tendency to produce more bonds. Hence, the suggestion of the second friend is correct.  


4 0
3 years ago
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