Hey there,
A scientist triples the temperature of a gas at constant pressure. By what factor does the gas’s volume change?
I believe that when the scientist triples the temperature of the gas at a certain and constant pressure, the factor of the gas volume would change most likely with the double amount of pressure that the scientist put in the first place.
~Jurgen
Answer:
In the reaction, Fe2+ is oxidized and MnO4- is reduced (option c.)
Explanation:
MnO₄⁻ + 5Fe²⁺ + 8H⁺ ---> Mn²⁺ + 5Fe³⁺ + 4H2O
Look all, the oxidation number.
Increase the oxidation number means, oxidation.
Decrease the oxidation number means, reduction.
Fe²⁺ → Fe³⁺ is increasing, the ox. number. Fe is oxidizing.
In MnO₄⁻, the Mn acts with +7, so in Mn²⁺ has decrease the ox. number.
Mn has reducted.
A voltaic cell operates such that the ions move from the negative electrode to the positive electrode.The negative electrode is the cathode while the positive electrode is the anode. This is in reverse to the cation-anion nomenclature. Hence, the answer to this problem is choice 2.
Answer:
37.15 h.
Explanation:
- The decay of radioactive elements obeys first-order kinetics.
- For first-order reaction: <em>kt = lna/(a-x).</em>
where, k is the rate constant of the reaction <em>(k = 2.4 x 10⁻² h⁻¹)</em>.
t is the time of the reaction <em>(t = ??? day)</em>.
a is the initial concentration of nuclides <em>(a = 100 %)</em>.
(a-x) is the remaining concentration of nuclides <em>(a - x = 100% - 59% = 41.0 %)</em>.
<em>∴ kt = lna/(a-x)</em>
(2.4 x 10⁻² h⁻¹)(t) = ln(100.0%)/(41.0%).
(2.4 x 10⁻² h⁻¹)(t) = 0.8916.
<em>∴ t </em>= (0.8916)/(2.4 x 10⁻² h⁻¹) = <em>37.15 h.</em>