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yaroslaw [1]
3 years ago
12

At STP, which sample contains the same number of molecules as 11.2 liters of CO2(g) at STP?

Chemistry
1 answer:
Lana71 [14]3 years ago
8 0
The answer is (3) 11.2 L of N2(g). When the choices are all gases, the number of molecules depends on the molar number of the gas. Under the condition of STP, the molar number of a gas is depends on volume only. So the same volume of gas has the same number of molecules.
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Geologists divide Earth’s long history into smaller units that make up the geologic time scale.
aleksandrvk [35]

False

Explanation:

The geologic time scale which simplifies earth's long history is broad division of deep time. It consists of a large and small divisions.

  • The geologic time scale is divided into large broad categories; called eons, eras, period and epoch.
  • The scale is merges absolute dating of events that has happened in geologic past and their relative ages.
  • Broad categories on the scale are further simplified into smaller units.
  • Relative age puts events in the order of their appearance using a couple of geologic principles.

Learn more;

A little on geology brainly.com/question/5751004

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8 0
3 years ago
Cu+2AgNO
baherus [9]

Answer:

Mass of Ag produced = 64.6 g

Note: the question is, how many grams of Ag is produced from 19.0 g of Cu and 125 g of AgNO3

Explanation:

Equation of the reaction:

Cu + 2AgNO3 ---> 2Ag + Cu(NO3)2

From the equation above, 1 mole of Cu reacts with 2 moles of AgNO3 to produce 2 moles of Ag and 1 mole of Cu(NO3)2.

Molar mass of the reactants and products are; Cu = 63.5 g/mol, Ag = 108 g/mol, AgNO3 = 170 g/mol, Cu(NO3)2 = 187.5 g/mol

To determine, the limiting reactant;

63.5 g of Cu reacts with 170 * 2 g of AgNO3,

19 g of Cu will react with (340 * 19)/63.5 g of AgNO3 =101.7 g of AgNO3.

Since there are 125 g of AgNO3 available for reaction, it is in excess and Cu is the limiting reactant.

63.5 g of Cu reacts to produce 108 * 2 g of Ag,

19 g of Cu will react to produce (216 * 19)/63.5 g of Ag = 64.6 g of Ag.

Therefore mass of Ag produced = 64.6g

6 0
3 years ago
Ammonia can be produced in the laboratory by heating ammonium chloride
AnnyKZ [126]

Answer:

Mass = 2.89 g

Explanation:

Given data:

Mass of NH₄Cl = 8.939 g

Mass of Ca(OH)₂ = 7.48 g

Mass of ammonia produced = ?

Solution:

2NH₄Cl   +  Ca(OH)₂     →    CaCl₂ + 2NH₃ + 2H₂O

Number of moles of NH₄Cl:

Number of moles = mass/molar mass

Number of moles = 8.939 g / 53.5 g/mol

Number of moles = 0.17 mol

Number of moles of Ca(OH)₂ :

Number of moles = mass/molar mass

Number of moles = 7.48 g / 74.1 g/mol

Number of moles = 0.10 mol

Now we will compare the moles of ammonia with both reactant.

                      NH₄Cl          :          NH₃

                          2              :           2

                         0.17          :          0.17

                   Ca(OH)₂         :          NH₃

                        1                :           2

                    0.10              :          2/1×0.10 = 0.2 mol

Less number of moles of ammonia are produced by ammonium chloride it will act as limiting reactant.

Mass of ammonia:

Mass = number of moles × molar mass

Mass = 0.17 mol × 17 g/mol

Mass = 2.89 g

6 0
2 years ago
If you can solve both<br> Will mark brainly<br> ASAP
MrRa [10]

Answer:

The main function sis the 2nd one and the substance provides the first 1.

Explanation:

Hope you finish the rest on your own, have fun!

7 0
3 years ago
Formula for Hydrocloric Acid.
Elden [556K]
HCl is the formula for hydrocloric acid
6 0
3 years ago
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