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Viefleur [7K]
2 years ago
14

Is WXY is a right triangle true or false

Mathematics
1 answer:
icang [17]2 years ago
6 0

Answer:

yes

Step-by-step explanation:

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Which numbers represent the lower quartile, the median, and the upper quartile of the following set of numbers?
kotegsom [21]

Answer:

Lower quartile: 85; median: 97; upper quartile 115.5

Step-by-step explanation:

4 0
3 years ago
Select all equations that are equivalent to 5x + 6/2= 3-(4x +12)​
Savatey [412]

Answer:

- 4/3

Step-by-step explanation:

6 0
2 years ago
Val tossed a coin 20 times. The results were 8 heads and 12 tails. What is the experimental probability of tossing heads?
Andrew [12]

Answer:

  2/5 or 0.40

Step-by-step explanation:

Val's result for heads is ...

  8/20 = 2/5 = 0.40

4 0
2 years ago
Use a 10-square model to solve. 12 is 10% of what number?
mestny [16]
I think the answer is 240 tho im not completely sure

hope this helps
3 0
3 years ago
Read 2 more answers
What is the easiest way to solve a quadratic equation?​
algol [13]

Answer: This is an opinion, look below! :)

Step-by-step explanation:

Factor the expression. To factor the expression, you have to use the factors of the {\displaystyle x^{2}}x^{2} term (3), and the factors of the constant term (-4), to make them multiply and then add up to the middle term, (-11). Here's how you do it:

Since {\displaystyle 3x^{2}}3x^{2} only has one set of possible factors, {\displaystyle 3x}3x and {\displaystyle x}x, you can write those in the parenthesis: {\displaystyle (3x\pm ?)(x\pm ?)=0}(3x\pm ?)(x\pm ?)=0.

Then, use process of elimination to plug in the factors of 4 to find a combination that produces -11x when multiplied. You can either use a combination of 4 and 1, or 2 and 2, since both of those numbers multiply to get 4. Just remember that one of the terms should be negative, since the term is -4.[3]

By trial and error, try out this combination of factors {\displaystyle (3x+1)(x-4)}(3x+1)(x-4). When you multiply them out, you get {\displaystyle 3x^{2}-12x+x-4}3x^{2}-12x+x-4. If you combine the terms {\displaystyle -12x}-12x and {\displaystyle x}x, you get {\displaystyle -11x}-11x, which is the middle term you were aiming for. You have just factored the quadratic equation.

As an example of trial and error, let's try checking a factoring combination for {\displaystyle 3x^{2}-11x-4=0}3x^{2}-11x-4=0 that is an error (does not work): {\displaystyle (3x-2)(x+2)}(3x-2)(x+2) = {\displaystyle 3x^{2}+6x-2x-4}3x^{2}+6x-2x-4. If you combine those terms, you get {\displaystyle 3x^{2}-4x-4}3x^{2}-4x-4. Though the factors -2 and 2 do multiply to make -4, the middle term does not work, because you needed to get {\displaystyle -11x}-11x, not {\displaystyle -4x}-4x.

7 0
2 years ago
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