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3 years ago

6

a restaurant serves 900 breakfast specials last week. This week, the number of breakfast specials the restaurant serve increased

by 15%. how many breakfast specials do the restaurants serve this week

1 answer:

Alexus [3.1K]3 years ago

5 0

First you have to figure out 15% of 900 so .15 times 900 which is 135 so then you do 900+135 which is now 1035

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Calculate the double integral. $$\iint_{R}{\color{red}4} xye^{x^{2}y}\hspace*{3pt}dA, \quad R = [0, 1] \times [0, {\color{red}7}

Lady_Fox [76]

Answer:

$\mathbf{\int \int _R \ 4xy e^{x^2 \ y} \ dA = 2 (e^7 -8)}$

Step-by-step explanation:

Given that:

$\int \int _R 4xye^{x^2 \ y} \ dA, R = [0,1]\times [0,7]$

The rectangle R = [0,1] × [0,7]

R = { (x,y): x ∈ [0,1] and y ∈ [0,7] }

R = { (x,y): 0 ≤ x ≤ 1 and 0 ≤ x ≤ 7 }

$\int \int _R \ 4xy e^{x^2 \ y} \ dA = \int^{7}_{0}\int^{1}_{0} 4xye^{x^2 \ y} \ dx dy$

$\int \int _R \ 4xy e^{x^2 \ y} \ dA = \int^{7}_{0} \begin {bmatrix} ye^{yx^2} \dfrac{4}{2y} \end {bmatrix}^1 _ 0 \ dy$

$\int \int _R \ 4xy e^{x^2 \ y} \ dA = \int^{7}_{0} \begin {bmatrix} ye^{y1^2} \dfrac{4}{2y} - ye^{y0^2} \dfrac{4}{2y} \end {bmatrix}\ dy$

$\int \int _R \ 4xy e^{x^2 \ y} \ dA = \int^{7}_{0} \dfrac{4}{2}(e^y -1) \ dy$

$\int \int _R \ 4xy e^{x^2 \ y} \ dA = \dfrac{4}{2}[e^y -1]^7_0 \ dy$

$\int \int _R \ 4xy e^{x^2 \ y} \ dA = 2 [(e^7 -7)-(e^0 -0)]$

$\int \int _R \ 4xy e^{x^2 \ y} \ dA = 2 [(e^7 -7)-1]$

$\mathbf{\int \int _R \ 4xy e^{x^2 \ y} \ dA = 2 (e^7 -8)}$

3 0

4 years ago

20 POINTS PLEASE HELP DONT HAVE TO SHOW WORK 2 ATTACHMENTS PLEASE ANSWER BOTH

Allisa [31]

$5^ \frac{3}{2}$

$5 \sqrt{3}$

7 0

4 years ago

If the translation is (x+1, y-4) and the image is (1,7), what is the preimage

EleoNora [17]

Answer:

The pre-image is the point (0,11)

Step-by-step explanation:

we know that

The rule of the translation is equal to

pre-mage------> image

(x,y) -----> (x+1,y-4)

so

we have that

(x+1,y-4)=(1,7)

so

x+1=1 -----> x=1-1=0

y-4=7 ----> y=7+4=11

therefore

The pre-image is the point (0,11)

4 0

3 years ago

For f(x)=2x+1 and g(x)=x^2-7, find (f+g)(x)

labwork [276]

For this case we have the following functions:

$f (x) = 2x + 1\\g (x) = x ^ 2-7$

We must find the following sum of functions:

(f + g) (x)

By definition we have to:

$(f + g) (x) = f (x) + g (x)\\(f + g) (x) = 2x + 1 + x ^ 2-7\\(f + g) (x) = x ^ 2 + 2x-6$

So, we have to:

$(f + g) (x) = x ^ 2 + 2x-6$

Answer:

$(f + g) (x) = x ^ 2 + 2x-6$

3 0

4 years ago

Solve the equation for x 23=5-2y

GaryK [48]

23=5-2y

Get y alone,

23-5= 18

18= -2y

Divide to find y

18/-2=-9

Y= -9

Or since you asked for x, X=no solutions.

Hope it helps ❤️

3 0

3 years ago