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Marina CMI [18]
4 years ago
9

Determine the profit-maximizingLOADING... prices when a firm faces two markets where the inverse demand curves are Market​ A: p

Subscript Upper Aequals80minus2Upper Q Subscript Upper A​, where demand is less​ elastic, and Market​ B: p Subscript Upper Bequals60minus1Upper Q Subscript Upper B​, where demand is more​ elastic, and Marginal Costequalsmequals20 for both markets.
Business
1 answer:
Gala2k [10]4 years ago
8 0

Answer:

Market A: P_{A} = 20.00

Market B: P_{B} = 20.00

Explanation:

Market A: P_{A} = 80 - 2Q_{A} ........................ (1)

Market B: P_{B} = 60 - 1Q_{B} ........................ (2)

MC = m = 20 ............................................... (3) for both markets

For Market A:

Profit maximizing price can be obtained when  P_{A} = m

Therefore, we have:

80 - 2Q_{A} = 20

80 - 20 = 2Q_{A}

60 = 2Q_{A}

Q_{A} = \frac{60}{2}

Q_{A} = 30

Substituting 50 for Q_{A} in equation (1), we have:

P_{A} = 80 - 2(30)

P_{A} = 80 - 60

P_{A} = 20.00

For Market B:

Profit maximizing price can be obtained when  P_{B} = m

Therefore, we have:

60 - 1Q_{B} = 20

60 - 20 = 1Q_{B}

40 = 1Q_{B}

Q_{B} = 40

Substituting 80 for Q_{B} in equation (2), we have:

P_{B} = 60 - 1(40)

P_{B} = 20.00

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Spence wants to have $176,000 in 7 years. He plans to make regular savings contributions of $13,100 per year for 7 years, with t
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$11,098.94

Explanation:

first we must calculate the future value of the 7 year annuity:

FV of an annuity = p x {[(1 + r)ⁿ - 1] / r}

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FV of an annuity = $13,100 x {(1.1718⁷ - 1) / 0.1718} = $13,100 x 11.8377 = $155,073.56

since he wants to have $176,000, he needs $20,926.44 more in 7 years (= $176,000 - $155,073.56)

X = FV / (1 + r)ⁿ

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5 0
3 years ago
Waygate's residential internet modem works well but is sensitive to power-line fluctuations. On average, this product hangs up a
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Answer:

a. In excess of .95

Explanation:

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f the short-run IS-LM equilibrium occurs at a level of income below the natural level of output, then in the long run the price
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Decrease; LM

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Thus this is the answer.

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a. Cost center

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