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3 years ago

6

Find the sum of 45. 65 2.60. 06 and 3

1 answer:

Vanyuwa [196]3 years ago

5 0

(.228263003 and^3 what i did was i replaced d3 to d^3

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How do I find 2 times as many

gregori [183]

You have to multiply whatever number your working with by 2

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3 years ago

Kat has 19 coins, all quarters and dimes, that are worth a total of $4. The system of equations that can be used to the number o

Luden [163]

<span>q + d=19 0.25q + 0.1d=4
</span><span> (d) -0.1(q + d=19) 0.25q + 0.1d=4 Opposites cancel -0.1q -0.1 d=1.9 0.25q + 0.1d=4</span>

7 0

3 years ago

A study indicates that 62% of students have have a laptop. You randomly sample 8 students. Find the probability that between 4 a

Scrat [10]

Answer:

72.69% probability that between 4 and 6 (including endpoints) have a laptop.

Step-by-step explanation:

For each student, there are only two possible outcomes. Either they have a laptop, or they do not. The probability of a student having a laptop is independent from other students. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

A study indicates that 62% of students have have a laptop.

This means that $n = 0.62$

You randomly sample 8 students.

This means that $n = 8$

Find the probability that between 4 and 6 (including endpoints) have a laptop.

$P(4 \leq X \leq 6) = P(X = 4) + P(X = 5) + P(X = 6)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 4) = C_{8,4}.(0.62)^{4}.(0.38)^{4} = 0.2157$

$P(X = 5) = C_{8,5}.(0.62)^{5}.(0.38)^{3} = 0.2815$

$P(X = 6) = C_{8,6}.(0.62)^{6}.(0.38)^{2} = 0.2297$

$P(4 \leq X \leq 6) = P(X = 4) + P(X = 5) + P(X = 6) = 0.2157 + 0.2815 + 0.2297 = 0.7269$

72.69% probability that between 4 and 6 (including endpoints) have a laptop.

3 0

3 years ago

Hey or range for each

topjm [15]

Answer : 100 meters 2:35/mile or 1:36/km 2:49/mile or 1:45/km

200 meters 2:35/mile or 1:36/km 2:52/mile or 1:47/km

400 meters 2:54/mile or 1:48/km 3:12/mile or 1:59/km

800 meters 3:23/mile or 2:06/km 3:48/mile or 2:21/km

1,500 meters 3:41/mile or 2:17/km 4:07/mile or 2:34/km

1 mile 3:43/mile or 2:19/km 4:13/mile or 2:37/km

5K 4:04/mile or 2:31/km 4:34/mile or 2:50/km

10K 4:14/mile or 2:38/km 4:45/mile or 2:57/km

Half Marathon

(13.11 miles / 21.098 km) 4:27/mile or 2:46/km 4:58/mile or 3:05/km

Marathon

(26.22 miles / 42.195 km) 4:41/mile or 2:55/km 5:10/mile or 3:13/km

Step-by-step explanation: sorry if this is wromg :/ ( but if it is please add me as the brainist answer )

7 0

3 years ago

-7y^6 x 3y^2 multiply

jeka94

Answer:

i think that answer is -21y^8

4 0

2 years ago

Read 2 more answers