The key for a stem and leaf plot is 3|4. which number is the stem? which number is the leaf?

Mathematics

1 answer:

Kisachek [45]3 years ago

4 0

Answer:

The number 3 is the stem.

The number 4 is the leaf.

Step-by-step explanation:

The Stem and Leaf Plot is a mathematical table used for the graphical representation of a data set. It involves splitting each data value into a stem (typically the first number, on the left) and a leaf (the last number, on the right).

The stem list is used for grouping data value downwards while the leaf values move rightward from its respective stem values and it's used for showing each data value within a group.

Also, the key of a stem and leaf plot is used as a guide on how to read the data set.

For example, the key for a stem and leaf plot is 3|4. Thus, the number 3 is the "stem" and the number 4 is the "leaf."

You might be interested in

Please Help! Solve this system of equations { 1/2x+6y+2 y=x+15

REY [17]

I dont know of you wanted the graph too so here

everything is in the pictures here, also sorry if I am wrong

4 0

3 years ago

Anna has a rectangular that is 33 inches and 75 inches. Find the perímeter of the rectangular in yards

charle [14.2K]

Answer:

6 yards

Step-by-step explanation:

Perimeter of a rectangle: 2a + 2b

2(33) + 2(75)

66 + 150

216 inches

216/12 gives us feet

18/3 gives us yards

6 yards

Answer: 6 yards

7 0

3 years ago

Find the length of each side of the triangle determined by the three points P1,P2, and P3. State whether the triangle is an isos

Tanya [424]

Answer:

The triangle is both an Isosceles triangle and a right triangle.

Step-by-step explanation:

Given the vertices of a triangle.

$P_{1} = (- 1, 4)$

$P_{2} = (6, 2)$ and

$P_{3} = (4, - 5)$

We find the distance between all the points to determine the length of each side of the triangle.

Distance between any two points, say, $(x_1, y_1)$ and $(x_2, y_2)$ is:

$\sqrt{\bigg ( \textbf{x}_{\textbf{2}} \hspace{1mm} \textbf{- x}_{\textbf{1}} \bigg )^{\textbf{2}} \textbf{+} \bigg( \textbf{y}_{\textbf{2}} \hspace{1mm} \textbf{- y}_{\textbf{1}} \bigg)^ {\textbf{2}}$