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3 years ago

Someone please help me

Mathematics

2 answers:

Zepler [3.9K]3 years ago

8 0

<u>Answer:</u>

$\frac{1 mi}{1.61km}$

<u>Step-by-step explanation:</u>

We are given the unit values of inch, foot and mile to convert into centimeters.

Using these conversion units, we are to determine whether which expression in the answer options can be used as the conversion factor to convert kilometers to miles.

So using the given conversion units, we can see that the following is the conversion factor to convert kilometers to miles.

$\frac{1 mi}{1.61km}$

Ratling [72]3 years ago

5 0

Answer:

1 mi/1.61 km

Step-by-step explanation:

we know that

1 mile= 1.61 kilometers

To convert 1 kilometer to miles

use proportion

1/1.61 mi/km=x/1 mi/km

x=1 mi/1.61 km

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What is the slope of the line represented by the equation y=x/3-5

Nana76 [90]

Answer:

a. 1/3

Step-by-step explanation:

y=x/3-5 (rewrite x - term)

y = (1/3) x + 5

recall that in the slope-intercept form of a linear equation y = mx + b

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3 years ago

Please help asap i will mark branlist

Serjik [45]

Answer:

C) Total Interest and Principal

Step-by-step explanation:

3 0

3 years ago

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First question, thanks. I believe there should be 3 answers

zysi [14]

Given: The following functions

$A)cos^2\theta=sin^2\theta-1$ $B)sin\theta=\frac{1}{csc\theta}$ $\begin{gathered} C)sec\theta=\frac{1}{cot\theta} \\ D)cot\theta=\frac{cos\theta}{sin\theta} \\ E)1+cot^2\theta=csc^2\theta \end{gathered}$

To Determine: The trigonometry identities given in the functions

Solution

Verify each of the given function

$\begin{gathered} cos^2\theta=sin^2\theta-1 \\ Note\text{ that} \\ sin^2\theta+cos^2\theta=1 \\ cos^2\theta=1-sin^2\theta \\ Therefore \\ cos^2\theta sin^2\theta-1,NOT\text{ }IDENTITIES \end{gathered}$

$\begin{gathered} sin\theta=\frac{1}{csc\theta} \\ Note\text{ that} \\ csc\theta=\frac{1}{sin\theta} \\ sin\theta\times csc\theta=1 \\ sin\theta=\frac{1}{csc\theta} \\ Therefore \\ sin\theta=\frac{1}{csc\theta},is\text{ an identities} \end{gathered}$

$\begin{gathered} sec\theta=\frac{1}{cot\theta} \\ note\text{ that} \\ cot\theta=\frac{1}{tan\theta} \\ tan\theta cot\theta=1 \\ tan\theta=\frac{1}{cot\theta} \\ Therefore, \\ sec\theta\ne\frac{1}{cot\theta},NOT\text{ IDENTITY} \end{gathered}$

$\begin{gathered} cot\theta=\frac{cos\theta}{sin\theta} \\ Note\text{ that} \\ cot\theta=\frac{1}{tan\theta} \\ cot\theta=1\div tan\theta \\ tan\theta=\frac{sin\theta}{cos\theta} \\ So, \\ cot\theta=1\div\frac{sin\theta}{cos\theta} \\ cot\theta=1\times\frac{cos\theta}{sin\theta} \\ cot\theta=\frac{cos\theta}{sin\theta} \\ Therefore \\ cot\theta=\frac{cos\theta}{sin\theta},is\text{ an Identity} \end{gathered}$

$\begin{gathered} 1+cot^2\theta=csc^2\theta \\ csc^2\theta-cot^2\theta=1 \\ csc^2\theta=\frac{1}{sin^2\theta} \\ cot^2\theta=\frac{cos^2\theta}{sin^2\theta} \\ So, \\ \frac{1}{sin^2\theta}-\frac{cos^2\theta}{sin^2\theta} \\ \frac{1-cos^2\theta}{sin^2\theta} \\ Note, \\ cos^2\theta+sin^2\theta=1 \\ sin^2\theta=1-cos^2\theta \\ So, \\ \frac{1-cos^2\theta}{sin^2\theta}=\frac{sin^2\theta}{sin^2\theta}=1 \\ Therefore \\ 1+cot^2\theta=csc^2\theta,\text{ is an Identity} \end{gathered}$

Hence, the following are identities

$\begin{gathered} B)sin\theta=\frac{1}{csc\theta} \\ D)cot\theta=\frac{cos\theta}{sin\theta} \\ E)1+cot^2\theta=csc^2\theta \end{gathered}$

The marked are the trigonometric identities

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1 year ago

At the mall Julie finds a sale at her favorite store. Two pair of pants will cost $42. If she wants to buy 5 pair, how much will

katovenus [111]

Divide 42 by two and then multiply by 5

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2 years ago

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D is the midpoint of RJ⎯⎯⎯⎯. R has coordinates (−4,7), and D has coordinates (2,−1). Identify the coordinates of J.

Aleksandr [31]

Answer:

$(8,-9)$

Step-by-step explanation:

If the x-coordinate of R is 6 units away from D's x-coordinate, then so will J's x-coordinate. If the y-coordinate of R is 8 units away from D's y-coordinate, then so will J's y-coordinate.

Side note/Extra information:

The line would be $y=\frac{-4}{3} x+\frac{5}{3}$

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2 years ago