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oksian1 [2.3K]
3 years ago
11

Which of the following relations is a function click on the graph until the correct graph appears

Mathematics
2 answers:
Nataliya [291]3 years ago
8 0

only the last one since the others don’t pass the vertical line test

which is when you draw a straight line down your function and if it hits 2 or more points it is not a function

BARSIC [14]3 years ago
4 0

Answer:

C.

Step-by-step explanation:

only the last one since the others don’t pass the vertical line test

which is when you draw a straight line down your function and if it hits 2 or more points it is not a function

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The grade point averages (GPA) for 12 randomly selected college students are shown on the right. Complete parts (a) through (c)
Ilya [14]

Answer:

\bar X =\frac{2.3+3.1+2.8+1.7+0.9+4+2.1+1.2+3.6+0.2+2.4+3.2}{12}=2.29

s=1.09

Step-by-step explanation:

For this case we have the following data given:

2.3 3.1 2.8

1.7 0.9 4.0

2.1 1.2 3.6

0.2 2.4 3.2

Since the data are assumedn normally distributed we can find the standard deviation with the following formula:

\sigma =\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n}}

And we need to find the mean first with the following formula:

\bar X = \frac{\sum_{i=1}^n X_i}{n}

And replacing we got:

\bar X =\frac{2.3+3.1+2.8+1.7+0.9+4+2.1+1.2+3.6+0.2+2.4+3.2}{12}=2.29

And then we can calculate the deviation and we got:

s=1.09

7 0
3 years ago
Read 2 more answers
24x + 30x = 3x + 24 + 4
Alinara [238K]

24x + 30x = 3x + 24 + 4


54x=3x+24+4


54x=3x+28


54x-3x=28


51x=28


X=28/51

7 0
3 years ago
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Please help asap will mark brainliest
melisa1 [442]
The second one because since n is not negative then nothing will be in the denominator
7 0
2 years ago
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Through:(5,1), parallel to y =1/5x-4
andrew-mc [135]

If the line is parallel to y=1/5x-4, the line must have the same slope.

So, the slope of your line is 1/5.

Now we need to find the y intercept. We should use the point given.

y=mx+b

1=1/5(5)+b

b=0

Equation: y=1/5x

3 0
3 years ago
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Expanding Logarithmic Expressions In Exercise, use the properties of logarithms to rewrite the expression as a sum, difference,
aev [14]

Answer:

The simplified expression is:

\ln{x} + \frac{\ln{(x-1)}}{2}

Step-by-step explanation:

We have those following logarithmic properties:

\ln{\frac{a}{b}} = \ln{a} - \ln{b}

\ln{a*b} = \ln{a} + \ln{b}

\ln{a^{n}} = n\ln{a}

In this problem, we have that:

\ln{x^{2}(x-1)}^{1/2}

Applying these properties

\frac{1}{2}*(\ln{x^{2} + \ln{(x-1)})

\ln{x} + \frac{\ln{(x-1)}}{2}

6 0
3 years ago
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