<span>Form a sequence that has two arithmetic means between -13 and 89. a. -13, 33, 43, 89 c. -13, 21, 55, 89 b. -18, -36, -72, -144 d. -18, -81, -144
Solution:
Since it has to be between -13 and 89, letter d and b are not anymore considered to be the answer.
for a:
33-(-13)=46=d
43-33=10=d the value for this d is different from the two sequence,
89-43=46=d
they have different value for d, thus this is not the answer!
for c:
21-(-13)=34=d
55-21=34=d
89-55=34=d
they have the same value for d, thus the correct answer is </span><span> c. -13, 21, 55, 89</span>
Answer:
Step-by-step explanation:
2 <u>| 500</u>
2 <u>| 250</u>
5 <u>| 125</u>
5 <u>| 25</u>
5 <u>| 5</u>
1 <u>| 1</u>
Prime factorisation of <u>500 = 2 × 2 × 5 × 5 × 5 × 1</u>
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Hope it helps.
ᏒᎯᎨᏁᏰᎾᏯᏕᎯᏝᎿ2222
The third set of angles is complementary. Complementary angles are angles that add up to 90°.
56° + 34° = 90°
