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frosja888 [35]
3 years ago
11

PLEASE HELP ME SIMPLIFY THIS PLEASE SHOW WORK TO! THANK YOU 3/4x + 11 - 5 1/2 + 1/4x

Mathematics
1 answer:
Svet_ta [14]3 years ago
6 0

Answer:

x-29/2

Step-by-step explanation:

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Read 2 more answers
It appears that people who are mildly obese are less active than leaner people. One study looked at the average number of minute
fredd [130]

Answer:

0.0322; 0.9929

Step-by-step explanation:

Since the data is normally distributed, we use z scores for these probabilities.

The formula for a z score of a sample mean is

z=\frac{\bar{X}-\mu}{\sigma \div \sqrt{n}}

For the sample of mildly obese people, the mean, μ, is 371; the standard deviation, σ, is 65; and the sample size, n, is 6.

Using 420 for X,

z = (420-371)/(65÷√6) = 49/(65÷2.4495) = 49/26.5360 ≈ 1.85

Using a z table, we see that the area under the curve to the left of this is 0.9678.  However, we want the area to the right, so we subtract from 1:

1-0.9678 = 0.0322

For the sample of lean people, the mean, μ, is 528; the standard deviation, σ, is 108; the sample size, n, is 6.

Using 420 for X, we have

z = (420-528)/(108÷√6) = -108/(108÷2.4495) = -108/44.0906 ≈ -2.45

Using a z table, we see that the area under the curve to the left of this is 0.0071.  We want the area under the curve to the right, so we subtract from 1:

1-0.0071 = 0.9929

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3 years ago
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