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tresset_1 [31]
3 years ago
11

Anyone know the answer ?

Mathematics
1 answer:
zepelin [54]3 years ago
5 0

Answer:

I think it's 48000

Step-by-step explanation:

mult.. them!!

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Is there a relationship between the area and the perimete of a rectangle. Explain
Nady [450]
The area is another way of say perimeter. it's the inside area of the rectangle
5 0
3 years ago
5. (9) Letf- ((-2, 3), (-1, 1), (0, 0), (1,-1), (2,-3)) and let g- ((-3, 1), (-1, -2), (0, 2), (2, 2), (3, 1)j. Find: a. (g f (0
pashok25 [27]

Answer:  g(f(0)) = 2 and  (f ° g)(2) = -3.

Step-by-step explanation:  We are given the following two functions in the form of ordered pairs :

f = {(-2, 3), (-1, 1), (0, 0), (1,-1), (2,-3)}

g = {(-3, 1), (-1, -2), (0, 2), (2, 2), (3, 1)} .

We are to find g(f(0))  and   (f ° g)(2).

We know that, for any two functions p(x) and q(x), the composition of functions is defined as

(p\circ q)(x)=p(q(x)).

From the given information, we note that

f(0) = 0,  g(0) = 2,  g(2) = 2  and  f(2) = -3.

So, we get

g(f(0))=g(0)=2,\\\\(f\circ g)(2)=f(g(2))=f(2)=-3.

Thus,  g(f(0)) = 2 and  (f ° g)(2) = -3.

8 0
3 years ago
Adirondack Savings Bank (ASB) has $5 million in new funds that must be allocated to home loans, personal loans, and automobile l
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Ggvvvv cds exhhhbdfxeccff
5 0
3 years ago
Use the substitution of x=e^{t} to transform the given Cauchy-Euler differential equation to a differential equation with consta
kherson [118]

By the chain rule,

\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{\mathrm dy}{\mathrm dt}\dfrac{\mathrm dt}{\mathrm dx}\implies\dfrac{\mathrm dy}{\mathrm dt}=x\dfrac{\mathrm dy}{\mathrm dx}

which follows from x=e^t\implies t=\ln x\implies\dfrac{\mathrm dt}{\mathrm dx}=\dfrac1x.

\dfrac{\mathrm dy}{\mathrm dt} is then a function of x; denote this function by f(x). Then by the product rule,

\dfrac{\mathrm d^2y}{\mathrm dx^2}=\dfrac{\mathrm d}{\mathrm dx}\left[\dfrac1x\dfrac{\mathrm dy}{\mathrm dt}\right]=-\dfrac1{x^2}\dfrac{\mathrm dy}{\mathrm dt}+\dfrac1x\dfrac{\mathrm df}{\mathrm dx}

and by the chain rule,

\dfrac{\mathrm df}{\mathrm dx}=\dfrac{\mathrm df}{\mathrm dt}\dfrac{\mathrm dt}{\mathrm dx}=\dfrac1x\dfrac{\mathrm d^2y}{\mathrm dt^2}

so that

\dfrac{\mathrm d^2y}{\mathrm dt^2}-\dfrac{\mathrm dy}{\mathrm dt}=x^2\dfrac{\mathrm d^2y}{\mathrm dx^2}

Then the ODE in terms of t is

\dfrac{\mathrm d^2y}{\mathrm dt^2}+8\dfrac{\mathrm dy}{\mathrm dt}-20y=0

The characteristic equation

r^2+8r-20=(r+10)(r-2)=0

has two roots at r=-10 and r=2, so the characteristic solution is

y_c(t)=C_1e^{-10t}+C_2e^{2t}

Solving in terms of x gives

y_c(x)=C_1e^{-10\ln x}+C_2e^{2\ln x}\implies\boxed{y_c(x)=C_1x^{-10}+C_2x^2}

4 0
3 years ago
Х
inn [45]

Answer:

y = 3(2)^x

Step-by-step explanation:

Given

The attached table

Required

Determine the exponential function

An exponential function is represented as:

y = ab^x

From the table;

(x,y)=(0,3)

So:

y = ab^x

3 = a * b^0

3 = a * 1

3 = a

a = 3

Also:

(x,y) = (1,6)

So:

y = ab^x

6 = a * b^1

6 = a * b

Substitute a = 3

6 = 3 * b

Solve for b

b = 2

So:

y = ab^x

y = 3(2)^x

3 0
3 years ago
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