State when the following equations and inequalities will be true and when they will be false.

1 answer:

6 0

' 36 = 9k ' is not an inequality. It's an equality, usually called an equation.

It's true whenever 'k' is 4, and false at any other time.

(You can determine that simply by dividing each side of the equation by 9.)

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Student enrollment at a local school is concerning the community because the number of students has dropped to 504, which is a 2

Trava [24]

Answer: The student enrollment the previous year was 630.

Step-by-step explanation: What we have currently is 504 students which represents 80 percent of the previous total number of students. We can conclude this because the question states clearly that the student enrollment dropped by 20 percent. In other words, we need to add back 20 percent to 80 percent to get the total 100 percent student enrollment from the previous year. The total number of students can be derived as follows;

If 504 equals 80 percent or (0.8), then 504 divided by 4 gives us 20 percent or (0.2)

20 percent times 5 equals 100 percent (or 0.2 times 5 equals 1)

Hence the calculation becomes;

(504/4) x 5 = Total

126 x 5 = 630

Therefore the total number of students enrollment the previous year was 630.

3 0

3 years ago

BD is a diameter of circle Q. If M_ACB=30°, what is M<DBA?

Papessa [141]

I also agree with answer C

8 0

3 years ago

How do you rewrite the fraction 11/12

navik [9.2K]

You can’t simplify that fraction.

5 0

3 years ago

A factory makes propeller drive shafts for ships. A quality assurance engineer at the factory needs to estimate the true mean le

borishaifa [10]

Answer:

$1000-1.96\frac{2}{\sqrt{4}}=998.04$

$1000+1.96\frac{2}{\sqrt{4}}=1001.96$

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Solution to the problem

The confidence interval for the mean is given by the following formula:

$\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (1)

Since the Confidence is 0.95 or 95%, the value of $\alpha=0.05$ and $\alpha/2 =0.025$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.025,0,1)".And we see that $z_{\alpha/2}=1.96$