3(x-5), using the distributive property, we get 3x - 15
Answer: 5,499,187,200
<u>Step-by-step explanation:</u>
A coin is tossed 5 times.
There are two options (heads or tails) so the possible outcomes are: 2⁵
A six-sided die is rolled 4 times.
There are six options so the possible outcomes are: 6⁴
A group of 3 cards are drawn (without replacement).
The first outcome has 52 options, the second has 51 options, and the third has 50 options: 52 x 51 x 50
Now if we want the coin AND the die AND the cards, we have to multiply all of their possible outcomes:
2⁵ x 6⁴ x 52 x 51 x 50
= 32 x 1296 x 132,600
= 5,499,187,200
Answer:
Yes, this is a valid inference because she took a random sample of the neighborhood.
Step-by-step explanation:
As her survey was non bias and completely random and she found that 15% of the families would participate in the event. She claims that 15% of the neighborhood families would be expected to participate in the sports event. So, yes, this is a valid inference because she took a random sample of the neighborhood.
The preferred gig is the first one since its today's worth is greater than the today's value of the second gig
What is the today's worth of $5000 each year?
The worth of the second gig, which pays $5000 every year for the next 6 years in today's dollar is the present value of all the six annual cash flows discounted using the present value formula of an ordinary annuity as shown below:
PV=PMT*(1-(1+r)^-N/r
PV=present value of annual payments for 6 years=unknown
PMT=annual payment=$5000
r=required return=discount rate=8%
N=number of annual cash flows=6
PV=$5000*(1-(1+8%)^-6/8%
PV=$5000*(1-(1.08)^-6/0.08
PV=$5000*(1-0.630169626883105)/0.08
PV=$5000*0.369830373116895
/0.08
PV=$23,114.40
The fact that the present value of the second option which pays $5000 annually is lesser than the amount receivable immediately, which is $25,000, hence, the first gig is preferred
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Answer:
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Step-by-step explanation:
