Answer:
Tn = 64-4n
Step-by-step explanation:
The nth term of an AP is expressed as:
Tn = a+(n-1)d
a is the common difference
n is the number of terms
d is the common difference
Given the 6th term a6 = 40
T6 = a+(6-1)d
T6 = a+5d
40 = a+5d ... (1)
Given the 20th term a20 = -16
T20 = a+(20-1)d
T20 = a+19d
-16 = a+19d... (2)
Solving both equation simultaneously
40 = a+5d
-16 = a+19d
Subtracting both equation
40-(-16) = 5d-19d
56 = -14d
d = 56/-14
d = -4
Substituting d = -4 into equation
a+5d = 40
a+5(-4) = 40
a-20 = 40
a = 20+40
a = 60
Given a = 60, d = -4, to get the nth term of the sequence:
Tn = a+(n-1)d
Tn = 60+(n-1)(-4)
Tn = 60+(-4n+4)
Tn = 60-4n+4
Tn = 64-4n
I think it’s the number 3 I’m not sure I’m learning this stuff rn I’m getting the hang of it just it’s hard and not hard at the same time
The estimated probability would be 0.1... I had this test yesterday. hope this helps
Answer:
BC ≈ 8.9 units
Step-by-step explanation:
Using the cosine ratio in the right triangle
cos36° = 
= 
= 
( multiply both sides by 11 )
11 × cos36° = BC , then
BC ≈ 8.9 ( to the nearest tenth )
Answer:
75 Arrangements
Step-by-step explanation:
Girl can secure 1st & 3rd, boy can secure 2nd position in : 6 x 5 x 5 = 150 ways ; As :
- 1st position holder can be chosen in 6 ways (among 6 girls)
- 2nd position holder can be chosen in 5 ways (among 5 boys)
- 3rd position holder can be chosen in ( among 5 remaining girls)
The arrangement of first, second & third :
It is same : If Girl G1 gets first rank & Girl G2 gets third rank, is same as ; Girl G1 gets third rank & Girl G2 gets first rank. So, two are considered the same group. Hence, number of arrangements are 150 / 2 = 75 arrangements.
