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Elena-2011 [213]
3 years ago
9

In the function f(t)= 200(.95)^t what is the rate of change

Mathematics
2 answers:
nirvana33 [79]3 years ago
8 0

Answer:

The rate of change is 5%.

Step-by-step explanation:

Given : Function f(t)=200(0.95)^t

To find: What is the rate of change?

Solution :

The given function is an exponential function as it is in form f(x)=ab^x

in which b is the factor of rate,

If b=1+r then r is the growth rate

If b=1-r then r is the decay rate.

We have given b=0.95

So, 0.95=1-r

r=1-0.95

r=0.05

i.e, It is a decay rate with 5%.

Therefore, The rate of change is 5%.

Vikentia [17]3 years ago
7 0
F(t) = 200(0.95)^t = 200(1 - 0.05)^t 
<span>rate is 5% decay per unit of time.

Hopefully that is correct & I hope I helped :)</span>
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Answer:

L = 70

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P = 2L + 2W

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P = 4x + 12 + 2x

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