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Nataly [62]
3 years ago
5

PLEASE HELP WITH MATHH

Mathematics
1 answer:
Scorpion4ik [409]3 years ago
5 0

Answer:

i think the answer is 76cm im pretty sure it is

Step-by-step explanation:

if so mark this as brainliest answer!!!

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6m^2 + 7n<br>Identify the constant, variable, and terms​
Leokris [45]
<h3>Answer:</h3>

<u>Given equation</u> :- 6m² + 7n

where,

  • <u>Constant</u> = 0.
  • <u>Variable</u> = m, n.
  • <u>Terms</u> = 6m² , 7n.
6 0
3 years ago
WILL MARK BRAINLIEST TO QUICKEST ANSWER! PLEASE HURRY
Evgesh-ka [11]
There seems to be a flaw with this question because it says that there are five x-intercepts but the given information only gives you 4 x-intercepts to work with.

Even means the graph is symmetric about the y-axis

The best answer is <span>A.(–6, 0), (–2, 0), and (0, 0)

because you do not have to worry about another point (0,0). Plus we need (-6,0) for it to be symmetric with (6,0).

Consider function f(x) = x²(x-6)(x+6)(x+2)</span>²(x-2)<span>². It is even and fits these conditions as it has x-intercepts at (6,0), (-6,0), (-2,0), (2,0), and (0,0). again, the question does not tell us the fifth x-intercept, so we need to assume that there is another one that needs to be there...and so (-2,0) must have (2,0) for it to be even as well.</span>
4 0
3 years ago
Read 2 more answers
Write mixed number for p so that 3 1/4 × p is more than 3 1/4
Sholpan [36]

Answer:

1 3/5

Step-by-step explanation:

Anything larger than 1 multiplied by 3 1/4 would result in a number more than 3 1/4.

8 0
3 years ago
7th grade math help me please :(.
Anettt [7]
6a: 11x+9
6b: 5y+14
6c: -3c-10
6d: 15x+10y
6e: -2n+13n
6f: 5w-5z
6g: 19x+8y+9
6h: 11a+4b-5

hope this helps and is correct!!
8 0
3 years ago
In the triangle pictured, let A, B, C be the angles at the three vertices, and let a,b,c be the sides opposite those angles. Acc
Troyanec [42]

Answer:

Step-by-step explanation:

(a)

Consider the following:

A=\frac{\pi}{4}=45°\\\\B=\frac{\pi}{3}=60°

Use sine rule,

\frac{b}{a}=\frac{\sinB}{\sin A}&#10;\\\\=\frac{\sin{\frac{\pi}{3}}&#10;}{\sin{\frac{\pi}{4}}}\\\\=\frac{[\frac{\sqrt{3}}{2}]}{\frac{1}{\sqrt{2}}}\\\\=\frac{\sqrt{2}}{2}\times \frac{\sqrt{2}}{1}=\sqrt{\frac{3}{2}}

Again consider,

\frac{b}{a}=\frac{\sin{B}}{\sin{A}}&#10;\\\\\sin{B}=\frac{b}{a}\times \sin{A}\\\\\sin{B}=\sqrt{\frac{3}{2}}\sin {A}\\\\B=\sin^{-1}[\sqrt{\frac{3}{2}}\sin{A}]

Thus, the angle B is function of A is, B=\sin^{-1}[\sqrt{\frac{3}{2}}\sin{A}]

Now find \frac{dB}{dA}

Differentiate implicitly the function \sin{B}=\sqrt{\frac{3}{2}}\sin{A} with respect to A to get,

\cos {B}.\frac{dB}{dA}=\sqrt{\frac{3}{2}}\cos A\\\\\frac{dB}{dA}=\sqrt{\frac{3}{2}}.\frac{\cos A}{\cos B}

b)

When A=\frac{\pi}{4},B=\frac{\pi}{3}, the value of \frac{dB}{dA} is,

\frac{dB}{dA}=\sqrt{\frac{3}{2}}.\frac{\cos {\frac{\pi}{4}}}{\cos {\frac{\pi}{3}}}\\\\=\sqrt{\frac{3}{2}}.\frac{\frac{1}{\sqrt{2}}}{\frac{1}{2}}\\\\=\sqrt{3}

c)

In general, the linear approximation at x= a is,

f(x)=f'(x).(x-a)+f(a)

Here the function f(A)=B=\sin^{-1}[\sqrt{\frac{3}{2}}\sin{A}]

At A=\frac{\pi}{4}

f(\frac{\pi}{4})=B=\sin^{-1}[\sqrt{\frac{3}{2}}\sin{\frac{\pi}{4}}]\\\\=\sin^{-1}[\sqrt{\frac{3}{2}}.\frac{1}{\sqrt{2}}]\\\\\=\sin^{-1}(\frac{\sqrt{2}}{2})\\\\=\frac{\pi}{3}

And,

f'(A)=\frac{dB}{dA}=\sqrt{3} from part b

Therefore, the linear approximation at A=\frac{\pi}{4} is,

f(x)=f'(A).(x-A)+f(A)\\\\=f'(\frac{\pi}{4}).(x-\frac{\pi}{4})+f(\frac{\pi}{4})\\\\=\sqrt{3}.[x-\frac{\pi}{4}]+\frac{\pi}{3}

d)

Use part (c), when A=46°, B is approximately,

B=f(46°)=\sqrt{3}[46°-\frac{\pi}{4}]+\frac{\pi}{3}\\\\=\sqrt{3}(1°)+\frac{\pi}{3}\\\\=61.732°

8 0
3 years ago
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