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3 years ago

What is the slope-intercept form of the equation of a line that passes through (5, -4) and has a slope of 34?

1 answer:

6 0

One way to find the slope-intercept form is to plug the given values into point-slope form, y - y_{1} = m (x - x_{1}), where x_{1} and y_{1} are the coordinate points and m is the slope. Then, you solve for y.

y - y_{1} = m (x - x_{1}) Plug in the values
y - (-4) = 34 (x - 5) Fix the minus negative four
y + 4 = 34 (x - 5) Use the Distributive Property
y + 4 = 34x - 170 Subtract 4 from both sides
y = 34x - 174

The slope-intercept form of the equation that passes through (5, -4) and has a slope of 34 is y = 34x - 174.

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A woman wishes to rent a house within 9 miles of her work. If she lives x miles from her work, her transportation cost will be c

I am Lyosha [343]

Answer:

the woman has to live 1 mile from work to minimize the expenses

Step-by-step explanation:

Given the data in the question;

the distance within 9 miles ⇒ 0 < x > 9

Total costs Q = cx + 4c/( x + 1)

costs should be minimum ⇒ dQ/dx = 0

⇒ d/dx [ cx + 4c/( x + 1) ] = 0

⇒ ( x + 1)² = 4

take square root of both side

√[ ( x + 1)² ] = √4

x + 1 = 2

x = 2 - 1

x = 1

Therefore, the woman has to live 1 mile from work to minimize the expenses

5 0

3 years ago

A scale on a map shows that 2.5 centimeters represent 15 kilometers.

MrRissso [65]

Answer:

cm for centimeters, km for kilometers.

If 2.5cm → 15 km, then

17.5 cm → x km

x= (15km*17.5cm)/(2.5cm)=105 km

Step-by-step explanation:

4 0

3 years ago

What is 8q+6;q=2 its expression for the given value of the variable

Leya [2.2K]

Answer:

8q + 6 = 8*2 + 6 = 16 + 6 = 22

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3 years ago

Write the equation in slope intercept form points (-11,6) (5,-2)

love history [14]

The slope intercept formula would be $- \frac{1}{2}$

6 0

3 years ago

What is the discontinuity and zero of the function

lukranit [14]

The discontinuity are the point wherein the function is not defined.
The zeros are the points wherein f(x)=0.
Computing the discontinuity points:
Set $x-1=0$ then the discontinuity point is at $x=1$ .
Comptine the zeroes:
Set $3x^2+x-4=0$
Compute the discriminant: $1^2-4(3)(-4)=49=7^2.$
Then with quadratic formula we get the solutions:
$(-1-7)/6=-8/6\\(-1+7)/6=1$
The two zeros are $\dfrac{-8}{6},1$

7 0

3 years ago