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2 years ago

Solve the system of linear equations by substitution.

2 answers:

5 0

Answer:
x= 29/11 or y= 25/11
Step-by-step explanation:
2x - y= 3 ...........equation 1
x + 5y= 14 ............equation 2
Make x the subject of the formula in equation 2
x= 14 - 5y ..............equation 3
Substitute x=14 - 5y in equation 1
2(14- 5y) - y=3
28 - 10y - y=3
Collect like terms
-10y - y=3 - 28
-11y= -25
divide both sides by coefficient of y
-11y/-11 = -25/-11
y= 25/11
Substitute y= 25/11 in equation 3
x=14 - 5(25/11)
x= 14 - 125/11
x= 29/11

SVEN [57.7K]2 years ago

3 0

Answer:

Answer:

x= 29/11 or y= 25/11

Step-by-step explanation:

2x - y= 3 ...........equation 1

x + 5y= 14 ............equation 2

Make x the subject of the formula in equation 2

x= 14 - 5y ..............equation 3

Substitute x=14 - 5y in equation 1

2(14- 5y) - y=3

28 - 10y - y=3

Collect like terms

-10y - y=3 - 28

-11y= -25

divide both sides by coefficient of y

-11y/-11 = -25/-11

y= 25/11

Substitute y= 25/11 in equation 3

x=14 - 5(25/11)

x= 14 - 125/11

x= 29/11

Step-by-step explanation:

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