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yawa3891 [41]
3 years ago
8

If angle ABC equals 130, what would the vertical angle equal to?

Mathematics
1 answer:
Mariulka [41]3 years ago
7 0

Answer:

400

Step-by-step explanation:

400

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A rectangle that measures 2 inches by 4 inches.<br> What is the area of the rectangle?
larisa86 [58]

Answer:

8 in

Step-by-step explanation:

because 4 x 2 = 8 inches squared

5 0
3 years ago
Read 2 more answers
I need help with this question plz
Rudiy27

Answer:

y = 10/3x + 20

Step-by-step explanation:

First, we need to find the slope of the function. We can do that by using two points and inserting them into the slope formula. It can be any two but I'll just pick (3, 30) and (6, 40).

m = y₁ - y₂ / x₁ - x₂

m = 30 - 40 / 3 - 6

m = -10/-3

m = 10/3

Now we know the slope is 10/3.

In slope-intercept form, the y-intercept is the constant at the end of the equation. The table of values tells us that the y-intercept is located at (0, 20). So the equation of the linear function is y = 10/3x + 20.

8 0
3 years ago
Find one value of xxx that is a solution to the equation (2x+3) 2 −6x−9=0
vesna_86 [32]

(2x+3) ^2 −6x−9=0

(2x+3) (2x+3) −6x−9=0

Foil

4x^2 +6x+6x+9-6x-9=0

4x^2 +12x+9-6x-9=0

Combine like terms

4x^2 +6x=0

factor out 2x

2x(2x+3)=0

2x=0  2x+3=0

x=0       2x=-3

              x=-3/2

Answer x=-3/2, 0


3 0
3 years ago
What is the center and spread of the data
liraira [26]
Sorry if i am wrong but it's 40
7 0
3 years ago
Evaluate tan ( cos^-1 ( 1/8 ) ) , giving your answer as an exact value (no decimals)
vekshin1

\bf cos^{-1}\left( \cfrac{1}{8} \right)=\theta \qquad \qquad cos(\theta )=\cfrac{\stackrel{adjacent}{1}}{\stackrel{hypotenuse}{8}}\impliedby \textit{let's find the \underline{opposite}} \\\\\\ \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies \sqrt{c^2-a^2}=b \qquad \begin{cases} c=hypotenuse\\ a=adjacent\\ b=opposite\\ \end{cases} \\\\\\ \pm\sqrt{8^2-1^1}=b\implies \pm\sqrt{63}=b ~\hfill tan(\theta )=\cfrac{\stackrel{opposite}{\pm\sqrt{63}}}{\stackrel{adjacent}{1}} \\\\\\ ~\hspace{34em}


\bf \stackrel{\textit{keeping in mind that}}{tan\left(cos^{-1}\left( \frac{1}{8} \right) \right)}\implies tan(\theta )

5 0
3 years ago
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