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3 years ago

-12x +8y=-32 in slope-intercept form

Mathematics

2 answers:

Sergeeva-Olga [200]3 years ago

4 0

Answer:

y=3/2x-4

Step-by-step explanation:

First we add 12x to both sides

8y=12x-32

Now divide both sides by 8

y=3/2x-4

Tatiana [17]3 years ago

3 0

The slope-intercept form: y = mx + b

$-12x+8y=-32\qquad|\text{add 12x to both sides}\\\\8y=12x-32\qquad|\text{divide both sides by 8}\\\\y=\dfrac{12}{8}x-\dfrac{32}{8}\\\\\boxed{y=\dfrac{3}{2}x-4}$

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oksian1 [2.3K]

Answer:

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Step-by-step explanation:

I am going to assume your question meant the equation

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And simplifying for our answer

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Answer:

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3 years ago

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andreev551 [17]

Answer:

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Step-by-step explanation:

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3 years ago

Read 2 more answers

What must be the value of a and b for PQRS to be a parallelogram?

Mars2501 [29]

Answer:

a = 2

b = 4

Step-by-step explanation:

In parallelogram opposite sides are equal.

4a + b = 2a + 8

4a - 2a + b = 8

2a + b = 8 -----------------(I)

b = 8 - 2a

11b - 10a = 6b

11b - 6b -10a = 0

5b - 10a = 0 ---------(II)

Substitute b = 8 - 2a in equation (II)

5*(8-2a) - 10a = 0

5*8 - 2a * 5 - 10a = 0

40 - 10a - 10a = 0

40 - 20a = 0

-20a = - 40

a = -40/-20

a = 2

Plugin a = 2 in equation (I)

2*2 + b = 8

4 + b = 8

b = 8 -4

b = 4

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3 years ago