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Aleksandr-060686 [28]
2 years ago
14

Paul graphed the equation y=x. Which point does the graph not pass through?

Mathematics
1 answer:
scoray [572]2 years ago
6 0

Answer:    

c.(10,15)

Step-by-step explanation:

i am really sorry if this is wrong

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Clark Heter is an industrial engineer at Lyons Products. He would like to determine whether there are more units produced on the
Alborosie

Answer:

Step-by-step explanation:

Let the subscripts d and n represent day and night respectively

The null hypothesis is

H0 : μd ≥ μn

The alternative hypothesis is

H1 : μd < μn

it is a one-tailed and also a right left test because of the greater than symbol in the alternative hypothesis.

The decision rule is to reject H0: μd ≥ μn If 0.10 > p value

Since the population standard deviations are known, we would use the formula to determine the test statistic(z score)

z = (xd - xn)/√σd²/nd + σn²/nn

Where

xd and xn represents sample means for day and night respectively.

σd and σn represents population standard deviations for day and night respectively.

nd and nn represents number of samples

From the information given,

xd = 334

xn = 341

σd = 23

σ2 = 28

nd = 60

nn = 68

z = (334 - 341)/√23²/60 + 28²/68

= - 7/√20.34607843138

z = - 1.55

From the normal distribution table, the probability value corresponding to the z score is 0.061

Since the level of significance, 0.1 > 0.061, we would reject H0

Therefore, there is enough evidence to conclude that there are more units produced on the night shift than on the day shift.

8 0
2 years ago
Ello awnser this what is 1 area x 649= ???<br> write in te awnser box
soldier1979 [14.2K]

Answer:

Well I believe 1 x 649 equals 649 units as the area...

I tried my best! Hope this helps you!

6 0
3 years ago
Please help this is what this app is for helping students with school work/homework
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We know it's for helping students so chill but I'll help, the number is 9 million and it's in the millions. You see all you have to do is classify the place value and say what the number is called.
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