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skad [1K]
3 years ago
9

When simplifying 7x^0 and (7x)^0 are these the same of different?

Mathematics
1 answer:
Levart [38]3 years ago
6 0

Answer:

these are different

Step-by-step explanation:

7x^0 is only x to the 0th power

(7x)^0 the 0th power is distributed to both the 7 and x

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Paying 12$ to whoever can answer this question i created. MUST BE CORRECT
Furkat [3]

Answer:

x = 10

I used the Interior Angles of a Triangle Rule --The sum of all 3 interior angles in a triangle is always 180°.

(3x + 28) + (5x - 18) + 90° = 180°

Now i can get rid of the parentheses and combine like terms.

3x + 5x + 28 - 18 + 90 = 180

8x + 10 + 90 = 180

8x + 100 = 180

Then i subtract 100 from both sides to isolate x.

8x + 100 - 100 = 180 - 100

8x = 80

Then, i divide both sides by 8 to find x.

8x ÷ 8 = 80 ÷ 8

x = 10

5 0
4 years ago
work for a publishing company. The company wants to send two employees to a statistics conference. To be​ fair, the company deci
Yuki888 [10]

Answer:

(a) S = {MR, MJ, MD, MC, RJ, RD, RC, JD, JC, DC}

(b) The probability that Roberto and John attend the​ conference is 0.10.

(c) The probability that Clarice attends the​ conference is 0.40.

(d) The probability that John stays​ home is 0.60.

Step-by-step explanation:

It is provided that :

Marco (<em>M</em>), Roberto (<em>R</em>), John (<em>J</em>), Dominique (<em>D</em>) and Clarice (<em>C</em>) works for the company.

The company selects two employees randomly to attend a statistics conference.

(a)

There are 5 employees from which the company has to select two employees to send to the conference.

So the total number of ways to select two employees is:

{5\choose 2}=\frac{5!}{2!(5-2)!}=\frac{5\times 4\times 3!}{2\times 3!}=10

The 10 possible samples are:

MR, MJ, MD, MC, RJ, RD, RC, JD, JC, DC

(b)

The probability of the event <em>E</em> is:

P(E)=\frac{n(E)}{N}

Here,

n (E) = favorable outcomes

N = Total number of outcomes.

The variable representing the selection of  Roberto and John is, <em>RJ</em>.

The favorable number of outcomes to select Roberto and John is, 1.

The total number of outcomes to select 2 employees is 10.

Compute the probability that Roberto and John attend the​ conference as follows:

P(RJ)=\frac{n(RJ)}{N}=\frac{1}{10}=0.10

Thus, the probability that Roberto and John attend the​ conference is 0.10.

(c)

The favorable outcomes of the event where Clarice attends the conference are:

n (C) = {MC, RC, JC and DC} = 4

Compute the probability that Clarice attends the​ conference as follows:

P(C)=\frac{n(C)}{N}=\frac{4}{10}=0.40

Thus, the probability that Clarice attends the​ conference is 0.40.

(d)

The favorable outcomes of the event where John does not attends the conference are:

n (J') = MR, MD, MC, RD, RC, DC

Compute the probability that John stays​ home as follows:

P(J')=\frac{n(J')}{N}=\frac{6}{10}=0.60

Thus, the probability that John stays​ home is 0.60.

4 0
3 years ago
Can someone please explain to me how to solve this problem? I have the answer already all I need is to know how to solve the pro
omeli [17]

Answer:

Step-by-step explanation:

you have two supplementary angles,

both added up=180

7y+5y=12y

12y=180y=15

angle DBC=7y=15*7=105

5 0
3 years ago
Read 2 more answers
66<br> +23<br> What is the answer
Luden [163]

6 + 2 = 8

6 + 3 = 9

66 + 23 = 89

filler

5 0
3 years ago
13. The manager of a clothing store planned to give free turkeys to salespersons selling over $10,000 during the fall harvest sa
barxatty [35]

Answer:

7.27% of the salespersons received turkeys

Step-by-step explanation:

Of the 110 salespersons working at the store, only 8 sold over $10,000.

So those earned turkeys.

As a proportion, this is: 8/110 = 0.0727

To find the percentage, we multiply the proportion by 100%. So

0.0727*100% = 7.27%

7.27% of the salespersons received turkeys

4 0
3 years ago
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