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Mashcka [7]
3 years ago
15

The sale price of a swimming pool after a 18.5% discount is $1189.90. Find the original list price of the pool.

Mathematics
1 answer:
zaharov [31]3 years ago
7 0

Answer:

1460

Step-by-step explanation:

18.5% of 1460 = 270.1

1460 - 270.1 = 1189.9

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Sidana [21]
<span>slope
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Hello i really need help on this its just 3 short question pls dont answer if you dont know it
Veseljchak [2.6K]

Answer:

1.  m = 60

2. k = 55

3. v  =  182

8 0
2 years ago
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If x = 7 units and h = 5 units, then what is the area of the triangle shown.
lukranit [14]

Answer:

35

Step-by-step explanation:

base × height so just multiple 7 and 5

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3 years ago
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A baseball diamond is a square with side 90 ft. A batter hits the ball and runs toward first base with a speed of 31 ft/s. (a) A
julsineya [31]

Answer:

a) -13.9 ft/s

b) 13.9 ft/s

Step-by-step explanation:

a) The rate of his distance from the second base when he is halfway to first base can be found by differentiating the following Pythagorean theorem equation respect t:

D^{2} = (90 - x)^{2} + 90^{2}   (1)

\frac{d(D^{2})}{dt} = \frac{d(90 - x)^{2} + 90^{2})}{dt}

2D\frac{d(D)}{dt} = \frac{d((90 - x)^{2})}{dt}  

D\frac{d(D)}{dt} = -(90 - x) \frac{dx}{dt}   (2)

Since:

D = \sqrt{(90 -x)^{2} + 90^{2}}

When x = 45 (the batter is halfway to first base), D is:

D = \sqrt{(90 - 45)^{2} + 90^{2}} = 100. 62

Now, by introducing D = 100.62, x = 45 and dx/dt = 31 into equation (2) we have:

100.62 \frac{d(D)}{dt} = -(90 - 45)*31          

\frac{d(D)}{dt} = -\frac{(90 - 45)*31}{100.62} = -13.9 ft/s

Hence, the rate of his distance from second base decreasing when he is halfway to first base is -13.9 ft/s.

b) The rate of his distance from third base increasing at the same moment is given by differentiating the folowing Pythagorean theorem equation respect t:

D^{2} = 90^{2} + x^{2}  

\frac{d(D^{2})}{dt} = \frac{d(90^{2} + x^{2})}{dt}

D\frac{dD}{dt} = x\frac{dx}{dt}   (3)

We have that D is:

D = \sqrt{x^{2} + 90^{2}} = \sqrt{(45)^{2} + 90^{2}} = 100.63

By entering x = 45, dx/dt = 31 and D = 100.63 into equation (3) we have:

\frac{dD}{dt} = \frac{45*31}{100.63} = 13.9 ft/s

Therefore, the rate of the batter when he is from third base increasing at the same moment is 13.9 ft/s.

I hope it helps you!

4 0
3 years ago
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Two angles are complementary. mZT is (3x + 17)° and mZW is 19°<br> Solve for x and for mZT.
natima [27]

Answer:

x = 18

mZT = 71º

Step-by-step explanation:

Complementary angles total 90º

(3x + 17) + 19 = 90

Subtract 19 from both sides

3x + 17 = 71

mZT = 71º

Subtract 17 from both sides

3x = 54

Divide both sides by 3

x = 18

5 0
3 years ago
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