Question:
Morgan is playing a board game that requires three standard dice to be thrown at one time. Each die has six sides, with one of the numbers 1 through 6 on each side. She has one throw of the dice left, and she needs a 17 to win the game. What is the probability that Morgan wins the game (order matters)?
Answer:
1/72
Step-by-step explanation:
<em>Morgan can roll a 17 in 3 different ways. The first way is if the first die comes up 5, the second die comes up 6, and the third die comes up 6. The second way is if the first die comes up 6, the second die comes up 5, and the third die comes up 6. The third way is if the first die comes up 6, the second die comes up 6, and the third die comes up 5. For each way, the probability of it occurring is 1/6 x 1/6 x 1/6 = 1/216. Therefore, since there are 3 different ways to roll a 17, the probability that Morgan rolls a 17 and wins the game is 1/216 + 1/216 + 1/216 = 3/216 = 1/72</em>
<em>I had this same question on my test!</em>
<em>Hope this helped! Good Luck! ~LILZ</em>
Ok the parralelogram is 25 units and I think the angle of BCD would be 53. I got this by subtracting 127 from 180 since that should give you the whole square. and I got teh units by adding the lines BC and AB... Hope this helped
Answer:
1 hour and 8 minutes
Step-by-step explanation:
After travelling 1 hour you’ve reached 60 miles. So you go 1 mile/ minute.
You have then 8 miles left. You get: 8 minutes. Which gives us the answer:
1 hour and 8 minutes.
Answer:D 237x/421x-515
Step-by-step explanation:
Answer:
D
Step-by-step explanation:
