do you need to include the wiggle infront of the first bracket? if not;
(x+1) ÷ [(x^2+2) x (2x-3dx)]
x^2 x 2x = 2x^3
x^2 x -3dx = -3dx^3
2 x 2x = 4x
2 x -3dx = - 6dx
i cant find a way to make it equal 0 so i think the answer is just
x+1 over 2x^3 - 3dx^3 + 4x - 6dx as a fraction
Answer:
<h2>3) -82.</h2><h2>4)-70.</h2><h2>5) -15.</h2><h2>6)-14.</h2><h2>7)5</h2><h2>8)15</h2><h2>9)16</h2><h2>10 )16</h2><h2>11)64</h2><h2>12)21.</h2><h2>13)1500 in the middle (not above not below)</h2><h2>14)450 m</h2>
Answer:
v = 220 yd²
Step-by-step explanation:
Small portion
v = 5 * 4 * 3
v = 60 yd²
Large portion
v = 9 * 6 * 3
v = 162 yd²
Total
v = 60 + 162
v = 220 yd²
2n+14=14+2n so this one as an infinite number of solutions. The second one 1-x=-x-6 so you add x on both sides which results in it having no solutions.
First, lets note that

. This leads us with the following problem:

Lets add sin on both sides, and we get:

Now if we divide with sin on both sides we get:

Now we can remember how cot is defined, it is (cos/sin). So we have:

Now take the inverse of cot and we get:

In general we have

, the reason we have to add pi times n, is because it is a function that has multiple answers, see the picture: