Which equation a line that goes through the points (1, 5) and (-2,2)
1 answer:
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Answer:
x = 5
Step-by-step explanation:
Using Pythagoras' identity in the right triangle.
The square on the hypotenuse is equal to the sum of the squares on the other 2 sides, that is
x² + 9² = 16²
x² + 81 = 256 ( subtract 81 from both sides )
x² = 175 ( take the square root of both sides )
x = = 5
≈ 13.23 units ( to 2 dec. places )
Answer:
(A)T(–2, 4) ry-axis
Step-by-step explanation:
The graph showing triangles MNO and M"N"O" is attached below.
From the graph, the coordinates are:
- M(5,-4),N(3,-2) and O(1,-3)
- M"(-3,0), N"(-1,2) and O"(1,1)
When we <u>transform triangle MNO by (-2,4),</u> we obtain:
M'(3,0), N'(1,2) and O'(-1,1)
Next, we reflect M'N'O' the y-axis.
Note: When you reflect a point across the y-axis, the y-coordinate remains the same, but the x-coordinate is transformed into its opposite.
Therefore:
- Reflection of M'N'O' accross the y-axis gives: M"(-3,0), N"(-1,2) and O"(1,1).
Therefore, the sequence of transformations could be used to map triangle MNO onto M"N"O" is T(–2, 4) ry-axis.
The correct option is A.
